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What is the percent of lead in lead IV oxide Or how do i calculate it?
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
What is the mass of a sample containing 5.82 mol of zinc?
378.3g You multiply the RMM by the Concentration (mol) Mass(g)=Concentration(mol)*RMM
What is the mass of 1 mol of rubidium?
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.
What is the molar mass of MgS?
The molar mass of Mg = 24.305 g/mol
What is the mass in grams of 5.01 mol of xenon?
The mass in grams of 5,01 mol of xenon is 657,778 g.
How many formula units are in 50.0 g of PbO2?
Formula unit is (molar mass) * (6.0221421*10^23)Molar mass of PbO2 is239.2089 g/molMolar mass of 50.0g of PbO2 is 50/239.2089 g/molFormula unit of PbO2 is ( 50g/239.2089 g/mol) *(6.0221421*10^23)=(0.20902232316606948988938120613405mol) *(6.0221421*10^23units/mol)=1.2587621321781923665883669044087*10^23unitsor approx. 1,26.1023 formula units.
How many moles are there in 37 grams of calcium hydroxide?
Use the equationmol = mass / RFM (or RAM)mol = 37 / (40 + 16x2 + 1x2)mol = 37 / 74mol = 0.5
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the molar mass of sodium oxalate?
molar mass is 318 g/mol (2X27)+3(2X12+4X16)=318g/mol
How many grams does 3 moles of CO2 weigh?
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
What is the formula mass of CS2?
Formular mass is the sum of the atomic mass' of the corresponding elements. C = 12.011 g/mol S = 32.06 g/mol 12.011 g/mol + 2(32.06 g/mol)= 76.131 g/mol Therefore, the formula mass of CS2 is 76.131 g/mol.
What percentage composition of Al2O3 is aluminum?
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
What is the percent of lead in lead IV oxide Or how do i calculate it?
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
What is the mass of a sample containing 5.82 mol of zinc?
378.3g You multiply the RMM by the Concentration (mol) Mass(g)=Concentration(mol)*RMM
What is IO's mass?
Io (the moon of Jupier) has a mass of 8.9319×1022 kg
