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10kg of water contains 10l of water. So morality is 0.2mildm-3.
C1V1 = C2V24 x .04 = 1 x V2V2 = (4 x .04)/1= 160mLTherefore the volume of water that needs to be added is 120mL (minus the original volume).
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
This solution contain 26,3 g NaOH.
The concentration of this solution (in NaOH) is 40 g/L.
0.33 mol/kg
Because the molecule of NaOH can be recovered unchanged from the solution.
The molarity is 0,33.
The molarity is 0,2.
0.33 mol/kg
10kg of water contains 10l of water. So morality is 0.2mildm-3.
0.33 mol/kg (apex)
you can't make a primay standard solution with NaOh.as NaOh is said to be a secondary standard you have to establish the normality using some primary standard acids.
0.2
The molality is 0,2.
It is possible only if you evaporate the water.