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first determine the number ofmoles dissolved in given solution

then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.

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Q: What is the molality of a solution of 90 grams of glucose C6H12OSUB6 dissolved in 800 grams of water?
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Why does a 0.10 molality solution of NaCl have a higher boiling point and a lower freezing point than a 0.10 molality solution of C6H12O6?

The higher the molality the higher the boiling point and the lower the freezing point. Conversely, the lower the molality the lower the boiling point and the lower the freezing point. Now let's analyze the problem: The total molality of 0.10 m of NaCl is 0.20 m. This is based on the property of the ionic bond. Ionic bonds are salts and thus strong electrolytes, which means they break up into all of there constituents in solution. Since two substances make up sodium chloride (sodium and chlorine), that means you'll have two substances overall. Your total molality was .10, and you have two substances, which means you're left with 0.10 * 2 = 0.20 m. Glucose is made of covalent bonds which do NOT break up in solution. This means you are left with one substance, C6H12O6. So you have 0.10 * 1 = 0.10. You are left comparing 0.20m of NaCL and 0.10m of C6H12O6. The higher molality has the higher boiling point.


How is salt different from ammonia glucose and water?

Salt is an ionic compound, it forms ions when dissolved in water. An ionic solution conducts electricity; ammonia or glucose dissolved in water will not conduct electricity as they are molecules not ions. Table salt is an ionic compound, NaCl (Sodium ion and Chloride ion)


Compare the boiling and freezing points of 1m solution of glucose to a 1m solution of Cacl2. Why does CaCl2 have a higher boiling and a lower freezing Please explain not just say its 1m and then 3m?

Boiling and freezing points are colligative properties, meaning they depend on the number of solute particles dissolve in solution. Glucose is a molecular compound so it is one particle dissolved in solution. CaCl2 will dissociate into three particles in solution. There are three times as many particles present in solution when CaCl2 dissolves.


How many molecules of sucrose in 0.5 L of a one molar solution of sucrose?

A 1.0 molar solution would be made up by dissolving the the molecular weight of glucose (in grams) in one litre. The molecular weight of glucose is 180.1559g; so a 1.0M solution would be 180.1559g in 1 litre. A 0.5M solution would be half that strong, so that would need 90.0780g in 1 litre. For 500ml you'd need take half the weight into half the volume, so that would be 45.0390g dissolved in water and made up to 500ml.


Calculate the isotonic coefficient for NaCl if a 07M of NaCl solution equaled the hemolysis of14M glucose solution?

i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2

Related questions

What is the molality solution that has 3 mol of glucose in 6 kg if water?

This molality is 90,08 g/kg.


What is the molality of 7.80 percent by weight glucose solution?

Assuming that is is a solution of glucose in water, the answer is 93%.


What does 1M glucose solution mean?

1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.


What is the molality of solution that has 3 mol of glucose in 6 Kg of water?

3mol/6kg


What is the molality of a solution that has 3 mol of glucose in 6 kg of water?

3mol/6kg


What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?

4 mol over 0.800 kg


Will NaCl dissolved with glucose solution conduct electricity?

yes


What is the molality of a solution the has 3 mol of glucose on 6 kg of water?

Molality (m) is moles of solute per kg of solvent. 3 moles/6 kg = 0.5 molal.


What is the boiling point of glucose dissolved in water?

If 180g glucose is present in one litre of solution then boiling point is 100.52 Celsius.


One mole of sodium chloride and one mole of glucose are dissolved in the same volume of water in separate containers what happens to their colligative properties?

There is twice the change in colligative properties in the sodium chloride solution than in the glucose solution.


Why does a 0.10 molality solution of NaCl have a higher boiling point and a lower freezing point than a 0.10 molality solution of C6H12O6?

The higher the molality the higher the boiling point and the lower the freezing point. Conversely, the lower the molality the lower the boiling point and the lower the freezing point. Now let's analyze the problem: The total molality of 0.10 m of NaCl is 0.20 m. This is based on the property of the ionic bond. Ionic bonds are salts and thus strong electrolytes, which means they break up into all of there constituents in solution. Since two substances make up sodium chloride (sodium and chlorine), that means you'll have two substances overall. Your total molality was .10, and you have two substances, which means you're left with 0.10 * 2 = 0.20 m. Glucose is made of covalent bonds which do NOT break up in solution. This means you are left with one substance, C6H12O6. So you have 0.10 * 1 = 0.10. You are left comparing 0.20m of NaCL and 0.10m of C6H12O6. The higher molality has the higher boiling point.


If 154 grams of glucose are dissolved to yield one liter of solution what is the molarity of the solution?

Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------