Assuming it is pure water (so no other salts will cause a precipitate),
149.1g of potassium chloride dissolved in one liter of distilled water
Molarity means number of moles in a solute volume. So molarity is 2moldm-3.
The mass of sodium chloride is 233,76 g.
233,771 g sodium chloride
233771
233.771
2
This is a homogeneous solution of ammonium hydroxide in water.
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
This is a solution of 10 g KCl/100 g water.
Just add the two masses: 40 + 120 = 160 grams.
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
A 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.
mixture
Because you have 6.68 moles of Li2SO4 and 2.500 liters of water, the overall molarity of your solution is 2.67 M.
This is a homogeneous solution of ammonium hydroxide in water.
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity
gjghm
The weight of the solution and thereby the weight of the solute.
This is a solution of 10 g KCl/100 g water.
Solute X is soluble in water
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
35.3