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Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
The first solution (500 g/L) is more concentrated than the second (200 g/L).
25 % sucrose
Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)
First find the moles of CO2 by dividing 22 grams by the molecular weight of CO2(44.01g/mol) 22.0gCO2 1mole/44.01g CO2 = .50 molesCO2
In 500ml there are 3.5 grams. Therefore in 1 litre, there are 7g. 7/58.443 is 0.1198 molar.
5.0M Molarity is moles of solute/liters of solution. The molar mass of ethanol is 46.07 g/mol, so 115g of ethanol is 2.5 moles of ethanol. 500cc is the same as 0.5L. So 2.5 mol/0.5L = 5.0M
Molarity is per litre. So whatever you do to convert the volume back to per litre you have to do to the moles. 2.5/500, x1000 is 5 molar.
molarity of a solution means mols per liter.First, you need to convert 23 grams on NaCl into mols. 23g divided by molar mass (58.44g/mol) which gives you .394 mols.Now, you need to convert 500ml to L which moves the decimal three places to the left, giving you .500L of solution.Finally, divide the mols over solution to get .787M
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
It depends highly on the compound to be dissolved and the solvent. Molarity is measured my moles per litre, and if you don't know the molar mass of the compound, you can't work out the molarity.
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
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Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
80 gNaOH / 500 mL = (80 gNaOH / 40 gNaOH/molNaOH) / 0.500 L = 2.0 mol / 0.500 L = 4.0 mol/L
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
The first solution (500 g/L) is more concentrated than the second (200 g/L).