Use this:
C = mol / vol
so CNaCl = 4.2(mol) / 0.450(L) = 9.33 (mol/L) = 9.3 M
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, since the volume is 450 ml (0.45 L) and the number of moles of NaCl is 4.2 mol, the molarity would be 4.2 mol / 0.45 L = 9.33 M.
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
Molarity = moles/litermoles = 9.33 g Na2S x 1 mole/78 g = 0.1196 molesliters = 450 ml x 1L/1000 ml = 0.45 Lmolarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)
To find the molarity of the diluted solution, you can use the formula: M1V1 = M2V2. Plug in the values: (1.0 M)(120 mL) = M2(450.0 mL) to find M2. Solving for M2, you get M2 = (1.0 M)(120 mL) / 450.0 mL = 0.27 M.
You mean if the amount of solvent is changed from 450 mL to 1250 mL without changing the amount of HCl?2.3 M = (x mol/0.450 L) x = 0.450 x 2.3 = 1.035 mol HClx M = (1.035 mol/1.25 L) = 0.828 M
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
The answer is 6,023.1023.
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
Molarity = moles/litermoles = 9.33 g Na2S x 1 mole/78 g = 0.1196 molesliters = 450 ml x 1L/1000 ml = 0.45 Lmolarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)
To find out how many grams are dissolved in 450mL, you can use a proportion based on the given information. The drug concentration is 17g/100mL, so you can set up the proportion: 17g/100mL = x/450mL. Cross multiply and solve for x to find the amount of drug dissolved in 450mL.
To find the molarity of the diluted solution, you can use the formula: M1V1 = M2V2. Plug in the values: (1.0 M)(120 mL) = M2(450.0 mL) to find M2. Solving for M2, you get M2 = (1.0 M)(120 mL) / 450.0 mL = 0.27 M.
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
187.5 ml of the 6.0 Molar solution mixed with (I assume) 262.5 ml water will produce 450ml of 2.5M.This can be solved with a system of equations. Assign variables x and y to be the quantities of the two respective liquids, say x for the 6.0M solution and y for the water.We know one equation is x + y = 450ml.Also, if I make an equation of Molarity x qty, I get:6.0x + 0y = 450*2.5which is 6x = 1125So my system of equations is:6x = 1125x + y = 450From here you should be able to easily solve for x from the first equation, then substitute for x into the second equation to find y.You should really get this whole mixing thing down before you embark upon consumption of alcoholic beverages. Just a little advice. :) 1 shot Everclear does not equal 1 shot JD. Why? Different %alcohol by volume! Sorry about that tangent...
You mean if the amount of solvent is changed from 450 mL to 1250 mL without changing the amount of HCl?2.3 M = (x mol/0.450 L) x = 0.450 x 2.3 = 1.035 mol HClx M = (1.035 mol/1.25 L) = 0.828 M
450
224, 225
To find the number of molecules in 450 grams of NaSO4, we first need to calculate the number of moles using the molar mass of NaSO4 (142.04 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in the calculated moles.