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You mean if the amount of solvent is changed from 450 mL to 1250 mL without changing the amount of HCl?

2.3 M = (x mol/0.450 L) x = 0.450 x 2.3 = 1.035 mol HCl

x M = (1.035 mol/1.25 L) = 0.828 M

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Q: What is the molarity of HCl if 450 mL of 2.3 M HCl is diluted to 1250 mL?
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