You mean if the amount of solvent is changed from 450 mL to 1250 mL without changing the amount of HCl?
2.3 M = (x mol/0.450 L) x = 0.450 x 2.3 = 1.035 mol HCl
x M = (1.035 mol/1.25 L) = 0.828 M
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Factor in hcl ?
1.22Molarity (multiply) 0.076Liters = 0.09272Moles needed to neutralize. 0.09272Moles (divided by) 0.125Liters = 0.74176 Molarity HCl has a Molarity of 0.74176
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Factor in hcl ?
1.22Molarity (multiply) 0.076Liters = 0.09272Moles needed to neutralize. 0.09272Moles (divided by) 0.125Liters = 0.74176 Molarity HCl has a Molarity of 0.74176
The molarity is 0,041
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
The HCL concentration is 1.2M or 1.2N
We can use PV = nRT to find moles of HCl (1 atm)(4.60 L) = n(0.08206 L*atm/mol*K)(298.15 K) moles HCl = 0.188 moles Molarity = moles of solute/Liters of solution Molarity = 0.188 moles HCl/0.240 liters = 0.783 Molar HCl =============
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
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