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Q: What is the molarity of a solution that contains 612 grams of CaCl2 in 3.04 liters of solution?
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What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?

The molarity is 2,973.


What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?

Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.


If 3.0 mol of CaCl2 are added to water to make 0.500L of solution what is the concentration in molarity?

molarity is #moles divide by # liters, so 3.0 divided by 0.500 is 6.0 molarity (2 siginficant figures is all you are allowed)


What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?

The molarity is 2 mol/L.


What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?

2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.


Molarity of CL in 110 ml of a solution containing 5.55g of CaCl2?

0.909 or 0.91


How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?

The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.


How many moles of CaCl2 are in 250 ml of CaCl2 solution?

It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.


What is the concentration of a solution which contains 1 mole of CaCl2 dissolved in 2000 milliliters of solution?

1.00 m


How many grams of calcium chloride will you add to 250mL of water to make a 0.236 M solution?

Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g


What is the concentration of nitric acid in moles per liter in a sample which has density 1.41gm per ml and the mass percent of nitric acid is 69 percent?

Molarity is probably the most commonly used unit of concentration. It is the number of moles of solute per liter of solution (not necessarily the same as the volume of solvent!). Example: What is the molarity of a solution made when water is added to 11 g CaCl2 to make 100 mL of solution? Solution: 11 g CaCl2 / (110 g CaCl2 / mol CaCl2) = 0.10 mol CaCl2 100 mL x 1 L / 1000 mL = 0.10 L molarity = 0.10 mol / 0.10 L molarity = 1.0 M http://chemistry.about.com/od/lecturenotesl3/a/concentration.htm http://www.tpub.com/content/MIL-SPEC/MIL-P/MIL-P-71158/MIL-P-7115800013.htm http://www.tpub.com/content/armymedical/md0837/md08370139.htm


What is the osmolarity of a 0.12M CaCl2 solution?

All you do is take the total number of ions in the compound and multiply it by the molarity to calculate the osmolarity.Thus,0.12 * 3 = 0.36