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[Ne]3s1
Sodium has 11 electrons, and one valence electron To achieve noble gas configurations, it would have to gain 7 electrons, for a total of 18 like Argon has. But this gain is impossible. So Sodium loses one electron to look like Neon which has 10.
Sodium has the configuration Ne 3s2 . Sodium is group-1 element.
The sodium atom (Na) has 11 electrons. The electron configuration of sodium is 2-8-1. The third noble gas shell is the second energy level or shell, which can hold a maximum of 8 electrons. Therefore, the number of electrons in the third noble gas shell of sodium is 1.
Na+ = 1s2, 2s22p6, 3s0which is 2, 8, 0 of Neon
No, Na is sodium, an alkali metal. The noble gasses are in the far right column of the periodic table.
Neither, Sodium is an Alkali Metal.
[Ne]3s1
a noble gas.
Sodium has 11 electrons, and one valence electron To achieve noble gas configurations, it would have to gain 7 electrons, for a total of 18 like Argon has. But this gain is impossible. So Sodium loses one electron to look like Neon which has 10.
A noble gas is inert. However they sometimes sodium ions or mercury vapor.
That is correct. A noble gas (or at least all the noble gas elements heavier than helium) has an electron configuration of 8 electrons in its outer shell, and the sodium and chlorine ions in sodium chloride also have 8 electrons in their outer shell, just like a noble gas atom.
Sodium has the configuration Ne 3s2 . Sodium is group-1 element.
Sodium looses one electron to achieve noble gas electronic configuration.The formula of ion formed is Na+
The sodium atom (Na) has 11 electrons. The electron configuration of sodium is 2-8-1. The third noble gas shell is the second energy level or shell, which can hold a maximum of 8 electrons. Therefore, the number of electrons in the third noble gas shell of sodium is 1.
Neon being a noble gas doesn't bond with Sodium
Na+ = 1s2, 2s22p6, 3s0which is 2, 8, 0 of Neon