54,9 mmol of sulfur dioxide is equivalent to 3,517 g.
(Inlet SO2-Exit SO2)X100 ----------------------------- Inlet-(1.5xinletXExit)/100
In water SO2 reacts to form H2SO3 which is sulfurous acid.
1 Sulfur atom and 2 oxygen atoms. Its molecular formula is SO2
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
This reaction is the following:2 KMnO4 + SO2 = 2 MnO2 + K2SO4
The volume of 72 grams of SO2 is 27,4 L.
2.65moles * 64.1g = 169.6
1 mole SO2 = 64.064g SO2 0.45g SO2 x 1mol SO2/64.064g SO2 = 0.0070 mole SO2
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
.75 moles times 64 grams/mols = 48 grams
72 grams SO2 (1 mole SO2/64.07 grams)(6.022 X 1023/1 mole SO2) = 6.8 X 1023 molecules of sulfur dioxide ============================
5
48.045
25.6 g
The molecular mass of SO2 = 32 + 2(16) = 64. Then 64 g * 0.75 = 48 g.
T = 35 degrees celsius = 308.15 degrees KelvinP = 97 atmV = ?n = 16.0 g SO2 / 64.06 g SO2 = 0.250 mol SO2