Zero. the oxidation number of all elemnts in every form is zero
Zero The oxidation number of an element in any of its elemental forms (allotropes) is always zero
The oxidation state (or number) is zero. This is true for any element in any of its allotropic elemental forms.
Oxidation number of h is 2
The oxidation number for H is almost always 1+.
Yes, it can. When the element loses electron, the oxidation number increases and when it gains electron, the oxidation number decreases.
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
The oxidation number for H is +1, and the oxidation number for O is -1.
Manganese is a metal element. It shows the largest oxidation number.
Oxidation number of a free element is 0. Ex: Ag 2= 0
Oxidation number is oxidation states of an element. It can be positive or negative.
the oxidation number is 0
As a diatomic element, it would be neutral and = 0Refer to this site for other rules:http://www.brynmawr.edu/Acads/Chem/Chem103lc/GCoxidationnumber.htmlThe oxidation number of NO, nitrogen oxide, is +2.