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As SO42- has an overall -2 charge, The Oxygen has a -2 oxidation state, so to balance and give an overall -2 charge, the Sulfur has to have a +6 oxidation state.
(-2 x 4) + (s) = -2
s = +6
Wiki User
∙ 14y ago
Wiki User
∙ 8y agoThis is sulfate ion. Sulfur shows +6 oxidation number.
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What is formula for complete oxidation of methane?
YES...CH4 + SO42- → HCO3- + HS- + H2O, is only one formula.
What is oxidation number of k k2so4?
the oxidation number of each K is +1. But there are two K's so 1*2 is +2. the charge on the molecule has to equal 0, so the oxidation number of the S must be -2.
What element decreases its oxidation number in the following reaction bici2 na2so4 2 naci biso4?
None do. Let's look at each compound: BiCl2... this is Bi2+ and Cl- Na2SO4... this is Na+ and SO42- NaCl... this is Na+ and Cl- BiSO4... this is Bi2+ and SO42- So as you can see, nobody is changing its charge, so everyone's oxidation number stayed constant. Of course I am a bit confused by the fact that Bismuth does not ever form a +2 ion (only +3 and +5), so I would have to assume you meant Ba2+. But it would not change what I wrote up there. It would simply be a precipition reaction, not an oxidation-reduction reaction.
What is the oxidation state of S in SO3 2-?
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
What is the oxidation number of IF?
oxidation number of I is -1. oxidation number of F is +1.
What is the oxidation state of S in SO42-?
SO42- (our goal is to get -2 charge) Oxygen by default has a -2 oxidation number, and we have 4 total, -2 X 4 = -8, our goal is -2, so S is +6.
What is the oxidation state of SO42?
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
What is formula for complete oxidation of methane?
YES...CH4 + SO42- → HCO3- + HS- + H2O, is only one formula.
What is oxidation number of k k2so4?
the oxidation number of each K is +1. But there are two K's so 1*2 is +2. the charge on the molecule has to equal 0, so the oxidation number of the S must be -2.
What element decreases its oxidation number in the following reaction bici2 na2so4 2 naci biso4?
None do. Let's look at each compound: BiCl2... this is Bi2+ and Cl- Na2SO4... this is Na+ and SO42- NaCl... this is Na+ and Cl- BiSO4... this is Bi2+ and SO42- So as you can see, nobody is changing its charge, so everyone's oxidation number stayed constant. Of course I am a bit confused by the fact that Bismuth does not ever form a +2 ion (only +3 and +5), so I would have to assume you meant Ba2+. But it would not change what I wrote up there. It would simply be a precipition reaction, not an oxidation-reduction reaction.
What is the oxidation state of S in SO32?
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
What is the oxidation state of S in SO3 2-?
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
What is the oxidation number of IF?
oxidation number of I is -1. oxidation number of F is +1.
What is the oxidation number of HClO?
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
What is the oxidation number of zns?
Zn has oxidation number +2; S has oxidation number -2
What is the oxidation number of H2O2?
The oxidation number for H is +1, and the oxidation number for O is -1.
What is the Oxidation number of sand?
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
