+1 for Na, +3 for B and -1 for each H
The IUPAC rules would have H as +1 except when bonded to a metal. Boron is a metalloid so it would have an oxidation number on that rule would be -5. It depends what rule you have been taught.
H -->+1 He --> 0 Be --> B
-1 for each H, +3 for each B
0 in the elemental form, +3 in its compounds
oxidation number of I is -1. oxidation number of F is +1.
a)3 b)2 c)1 d)4 Fe is the transitional metal K3[Fe(CN)6] , we know that Potassium, K, has an oxidation number of +1 The oxidation number of CN= -1, so 6*CN has an oxidation number of -6 so therefore Fe - 6 = -3 Fe = -3 + 6 = +3 The oxidation number of Fe is +3. so A
B2 (O2)2 (OH)4 +12 -8 -4 going off this i'd say boron's O.S is +6
We know NaBH4 as sodium borohydride.
H -->+1 He --> 0 Be --> B
-1 for each H, +3 for each B
0 in the elemental form, +3 in its compounds
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
a)3 b)2 c)1 d)4 Fe is the transitional metal K3[Fe(CN)6] , we know that Potassium, K, has an oxidation number of +1 The oxidation number of CN= -1, so 6*CN has an oxidation number of -6 so therefore Fe - 6 = -3 Fe = -3 + 6 = +3 The oxidation number of Fe is +3. so A
Zn has oxidation number +2; S has oxidation number -2
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Oxidation number of Si is +4.Oxidation number of O is -2.