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14y ago

Oxygen in compounds "always" has an ON of -2. With four oxygens in one sulfate, this is so far a total of -8. However, there is also a 2- charge on the ion, so we subtract this from the total: -8 --2 = -8 + 2 = 6. Since sulphur is the only atom left, it must carry the whole of this charge, making its ON (and formal charge) +6.

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10y ago

S has an oxidation number of +6 in sulfate ion ( O is -2 the overall charge is -2 so S must be +6)

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11y ago

+6

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14y ago

+4

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7y ago

+6

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Q: What is the oxidation number of SO4 2?
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