The principal oxidation state of NA in NA2O2 and K in KO2 is +1
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
Oxidation state of K in KO2 is - 0.5 because its structure is K-O=O .
+1 for K -2 for each O +5 for N
-1
The principal oxidation state of NA in NA2O2 and K in KO2 is +1
-2 oxidation state
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
-1 oxidation state. This ion should be called Kallide
Oxidation state of K in KO2 is - 0.5 because its structure is K-O=O .
+1 for K -2 for each O +5 for N
the oxidation number of each K is +1. But there are two K's so 1*2 is +2. the charge on the molecule has to equal 0, so the oxidation number of the S must be -2.
The oxidation numbers for the atoms in the ionic compound KCl are K+1 and Cl-1.
+1 for K and -1 for Cl