0.2 mol of HCL will give 0.2 mol of H+ ions (strong acid; so full
ionization in water), same goes for 0.25 mol NaOH (strong alkali) that
will give 0.25 mol. of OH-.
H+ + OH- -> H2O
So effectively there'll be 0.05 mol of OH- after mixing 1 mol of each
HCL & NaOH, which translates to 0.025mol of OH- for every mol of the
mixture.
pH = 14 - log10(OH-) = 12.4
Strong acid with strong base always ends with neutral water and the resulting ions Na+ and Cl-, both neutral as well!
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
basic
This sodium hydroxide solution has a molarity of 0,25.
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Strong acid with strong base always ends with neutral water and the resulting ions Na+ and Cl-, both neutral as well!
It depends on the molarity of the solution
The molarity is 0,125 M.
Barium Hydroxide: Mass: 2.74g. Mr = 171. Moles = Mass (g)/Mr Therefore - 2.74/ 171 = 0.01602339181mols.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
4m
basic
This sodium hydroxide solution has a molarity of 0,25.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
6M
.13 (Plato)
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.