Strong acid with strong base always ends with neutral water and the resulting ions Na+ and Cl-, both neutral as well!
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
basic
This sodium hydroxide solution has a molarity of 0,25.
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
It is 11.3
It depends on the molarity of the solution
The molarity is 0,125 M.
Barium Hydroxide: Mass: 2.74g. Mr = 171. Moles = Mass (g)/Mr Therefore - 2.74/ 171 = 0.01602339181mols.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
4m
basic
This sodium hydroxide solution has a molarity of 0,25.
6M
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
.13 (Plato)
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
It is 11.3