The pH of a 10^-5 M KOH solution would be around 9. For a given concentration of a strong base like KOH, the pH can be calculated using the formula pH = 14 - pOH. Given that pOH = -log[OH-] and [OH-] = 10^-5 M in this case, pOH = 5. Therefore, pH = 14 - 5 = 9.
0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6
[OH-] = 1x10^-3 M[H+][OH-] = 1x10^-14[H+] = 1x10^-14/1x10^-3 = 1x10^-11pH = -log 1x10^-11 = 11Done another way:pOH = -log [OH-] = -log 1x10^-3 = 3pH + pOH = 14pH = 14 - 3 = 11
To find the H ion concentration in a KOH solution, first determine the hydroxide ion (OH-) concentration. Since KOH is a strong base, it fully dissociates in water. Therefore, the OH- concentration is equal to the KOH concentration, which is 4.8x10^-2 M. The H ion concentration can be calculated using the equation Kw = [H+][OH-], where Kw is the ion product of water (1.0x10^-14 at 25°C). From there, you can determine the H ion concentration by dividing Kw by the OH- concentration.
The pOH is 5,23.
0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6
[OH-] = 1x10^-3 M[H+][OH-] = 1x10^-14[H+] = 1x10^-14/1x10^-3 = 1x10^-11pH = -log 1x10^-11 = 11Done another way:pOH = -log [OH-] = -log 1x10^-3 = 3pH + pOH = 14pH = 14 - 3 = 11
To find the H ion concentration in a KOH solution, first determine the hydroxide ion (OH-) concentration. Since KOH is a strong base, it fully dissociates in water. Therefore, the OH- concentration is equal to the KOH concentration, which is 4.8x10^-2 M. The H ion concentration can be calculated using the equation Kw = [H+][OH-], where Kw is the ion product of water (1.0x10^-14 at 25°C). From there, you can determine the H ion concentration by dividing Kw by the OH- concentration.
"Little by little" is an English equivalent of the Italian phrase a poco a poco.Specifically, the preposition a literally means "at, to." The adverb poco means "little." The pronunciation is "ah POH-koh ah POH-koh."
The pOH is 5,23.
To calculate the concentration of hydroxide ions (OH-) from a given pH value, you can use the formula: [OH-] = 10^(-pH). For a pH of 1.12, the concentration of hydroxide ions would be [OH-] = 10^(-1.12) = 0.079 moles per liter.
e2an koh poh
Cosmopolitano is an Italian equivalent of 'cosmopolitan'. It's the masculine form of an adjective whose feminine equivalent is 'cosmopolitana'. Both forms are pronounced 'koh-smoh-poh-lee-TAH-no' and 'koh-smoh-poh-lee-TAH-nah', respectively.no, it's "cosmopolita" for both gender.
The pOH is 6,4.
To calculate the mass of KOH needed to make 400mL of 725 M KOH solution, you would use the formula: mass = volume (in L) * molarity * molar mass First, convert the volume from mL to L (400mL = 0.4 L). Then plug in the values for volume (0.4 L), molarity (725 M), and the molar mass of KOH (39.10 g/mol) to find the mass of KOH needed. mass = 0.4 L * 725 mol/L * 56.11 g/mol ≈ 131.78 grams.
To find the concentration of hydroxide ions (OH-) at pH 6, you can use the formula: OH- concentration = 10^-(14-pH). So, at pH 6, the concentration of OH- would be 1 x 10^-8 moles per liter.
Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH