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What is the pOH of 0.0347 M KOH?

Updated: 4/28/2022
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Q: What is the pOH of 0.0347 M KOH?
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What is the pH of a 0.04 M KOH solution?

0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6


What is the pH of a 1.0 10-3 M KOH solution?

[OH-] = 1x10^-3 M[H+][OH-] = 1x10^-14[H+] = 1x10^-14/1x10^-3 = 1x10^-11pH = -log 1x10^-11 = 11Done another way:pOH = -log [OH-] = -log 1x10^-3 = 3pH + pOH = 14pH = 14 - 3 = 11


What is the H ion concentration in a 4.8x10-2 M KOH solution?

pOH = -log(10)[OH^-] pOH = -log(10) [ 48. x 10^-2] pOH = - (-1.31875...) pOH = 1.31875... pH = 14 - pOH pH = 14 - 1.31875... pH = 12.68124... pH = 12.68


What is 'a poco a poco' when translated from Italian to English?

"Little by little" is an English equivalent of the Italian phrase a poco a poco.Specifically, the preposition a literally means "at, to." The adverb poco means "little." The pronunciation is "ah POH-koh ah POH-koh."


When the H in a solution is 1.7 109 M what is the pOH?

The pOH is 5,23.


How do you calculate OH- with a ph of 1.12?

pH + pOH = 14. So pOH = 14 - 1.12 = 12.88 pOH = -log[OH-] [OH-] = 1.31 x 10-13 M


Anu ano ang uri ng panahon mayroon ang unang Filipino?

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What is 'cosmopolitan' in Italian?

Cosmopolitano is an Italian equivalent of 'cosmopolitan'. It's the masculine form of an adjective whose feminine equivalent is 'cosmopolitana'. Both forms are pronounced 'koh-smoh-poh-lee-TAH-no' and 'koh-smoh-poh-lee-TAH-nah', respectively.no, it's "cosmopolita" for both gender.


If the pH of a solution is 10.7, what would the pOH be?

The pOH is 6,4.


What mass of KOH is needed to make 400mL of 725 M KOH?

I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================


If pH is 6 What is is OH?

pH + pOH = 14. So pOH = 14 - 6 = 8 pOH = -log[OH-] [OH-] = 10-8 M


How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?

Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH