RMS*SQRT(2)=V(peak)
or
115V*1.414= 162.63V(peak)
Source: What_is_the_conversion_for_rms_voltage_to_peak_to_peak_voltage
Vpeak = Vrms * sqrt(2)
Vpeak = Vrms * 1.414
169.68 Vpeak = 120 Vrms * 1.414
It is 2 times the square root of 2 times that voltage.
339
170 volts ac
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
For a sine wave ONLY - and assuming you are talking plus and minus 100V (200V peak to peak) - the RMS voltage is about 71V. (One half square root of 2 * single sided peak value)
A square wave will have the highest value since it has a peak, positive or negative, all of the time. Other wave shapes such as triangular and sine, have a lower value than this.
The root-mean-square (rms) value of a sinusoidal voltage or current is given by: Vrms = 0.707 Vmax and Irms = 0.707 ImaxSo, if the current has a peak-to-peak value of 10 A, then Imax will be half that value (5 A) , so the corresponding rms value is:Irms = 0.707 Imax = 0.707 x 5 = 3.54 A(Answer)
The rms value of a sine wave current is 0.707 Imax. So the answer to your quesion is 0.707 x 4 = 2.83 A.
A square wave has the highest RMS value. RMS value is simply root-mean-square, and since the square wave spends all of its time at one or the other peak value, then the RMS value is simply the peak value. If you want to quantify the RMS value of other waveforms, then you need to take the RMS of a series of equally spaced samples. You can use calculus to do this, or, for certain waveforms, you can use Cartwright, Kenneth V. 2007. In summary, the RMS value of a square wave of peak value a is a; the RMS value of a sine wave of peak value a is a divided by square root of 2; and the RMS value of a sawtooth wave of peak value a is a divided by cube root of 3; so, in order of decreasing RMS value, you have the square wave, the sine wave, and the sawtooth wave. For more information, please see the Related Link below.
The wave with the maximum RMS value, in comparision with the peak value, is the square wave.
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
Multiply the peak to neutral by .707 for a sine wave. The RMS value is the equivalent level available if it were DC, so it will always be lower than the peak value.
For a sine wave ONLY - and assuming you are talking plus and minus 100V (200V peak to peak) - the RMS voltage is about 71V. (One half square root of 2 * single sided peak value)
A square wave will have the highest value since it has a peak, positive or negative, all of the time. Other wave shapes such as triangular and sine, have a lower value than this.
100v divided by 1.41
The root-mean-square (rms) value of a sinusoidal voltage or current is given by: Vrms = 0.707 Vmax and Irms = 0.707 ImaxSo, if the current has a peak-to-peak value of 10 A, then Imax will be half that value (5 A) , so the corresponding rms value is:Irms = 0.707 Imax = 0.707 x 5 = 3.54 A(Answer)
Do you mean a "saw-tooth" wave? Also, a "peak value" is not an RMS value (by definition), it is simply the highest value attained (positive or negative) over the period of analysis.