A square wave will have the highest value since it has a peak, positive or negative, all of the time. Other wave shapes such as triangular and sine, have a lower value than this.
Triangular Wave
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
You are, presumably, referring to alternating current, in which case the 'maximum' current is the peak or amplitude of the waveform. The 'average' value of current is zero, because the average value of the first half of each cycle is negated by the average value over the second half of each cycle. This is why a.c. currents and voltages are always expressed in 'root-mean-square' (r.m.s.) values which is the value of an a.c. current that does the same amount of work as a given value of d.c. current. The r.m.s. value for a sinusoidal current (and voltage, as voltage and current are proportional) is 0.707 times the peak or maximum value.
RMS is the root mean square value.(in alternating current only)
All a.c. voltages are expressed in root-mean-square (r.m.s.) values, unless otherwise stipulated. So 12 V is an r.m.s value which, for a sinusoidal waveform, has an amplitude, or peak value, of 1.414 x 12 = 16.97 V. So its peak-to-peak value will be twice this amount -i.e. 33.94 V.
It is the highest value of the amplitude, called the peak value. Scroll down to related links and look at "RMS voltage, peak voltage and peak-to-peak voltage". Look at the figure in the middle below the headline "RMS voltage, peak voltage and peak-to-peak voltage".
Use an oscilloscope. That shows the voltage waveform and you can read the peak value.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
AC waveform is sinusoidal waveform it has both positives and negative cycles so we dont have a standard constant value to do Measurements so instead of using AC quantities we use ROOT mean square values which is obtained by dividing Vpp(peak to peak voltage) by 1.414AnswerThe rms-value of an AC current is the same as as the value of DC current that will do the same amount of work. For example, 10 A (rms) AC will do exactly the same amount of work as 10 A DC.
Unless otherwise stated, the value of an a.c. current or voltage is expressed in r.m.s. (root mean square) values which, for a sinusoidal waveform, is 0.707 times their peak value. The output of a voltage (or potential) transformer is no different, its measured voltage will be its r.m.s value which is lower than its peak value.
You are, presumably, referring to alternating current, in which case the 'maximum' current is the peak or amplitude of the waveform. The 'average' value of current is zero, because the average value of the first half of each cycle is negated by the average value over the second half of each cycle. This is why a.c. currents and voltages are always expressed in 'root-mean-square' (r.m.s.) values which is the value of an a.c. current that does the same amount of work as a given value of d.c. current. The r.m.s. value for a sinusoidal current (and voltage, as voltage and current are proportional) is 0.707 times the peak or maximum value.
RMS is the root mean square value.(in alternating current only)
All a.c. voltages are expressed in root-mean-square (r.m.s.) values, unless otherwise stipulated. So 12 V is an r.m.s value which, for a sinusoidal waveform, has an amplitude, or peak value, of 1.414 x 12 = 16.97 V. So its peak-to-peak value will be twice this amount -i.e. 33.94 V.
Not sure what you mean by Class A current. Normally, when measuring AC voltage or current you either measure the peak to peak value or the Root Mean Squared (RMS) value. Since RMS is essentially an average measured over time, it would always be less than Peak to Peak value.
When the AC waveform goes to one peak, the capacitor that follows the diode is charged to that peak value. When the AC waveform goes to the other peak, the same diode is reverse biased between the alternate peak value and the charged value of the capacitor. This differential voltage is two times peak voltage.
Average Current = 0.636 * (Peak Current)so Peak Current = (Average Current)/0.636RMSCurrent = 0.707 * (Peak Current)so Peak Current = (RMS Current)/0.707Because both equations are in terms of Peak Current, we can set them equal to each other.(Average Current)/0.636 = (RMS Current)/0.707(42.5)/0.636 = (RMS Current)/0.707thenRMS Current = (0.707)(42.5)/0.636 = 47.24 ampsAnother AnswerSince the average value of a single sine wave is zero, you cannot calculate its r.m.s. value!