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(32.07/80.07)*100 =40.0%
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.
Tin sulfate is made out of the elements tin, sulfur and oxygen. The mass numbers of tin, oxygen and sulfur are 117, 16 and 32 respectively. Therefore the molecular weight of the empirical formula is 215 g/mol.
Sulfur is closely match this puzzle. The density of 2 kg sulfur is double than 1 kg water. So if you weigh the sulfur in immersed state, the weight of sulfur will be 1 kg. Sulfur will displace about 1 kg water and will lose the same weight. After taking out of water, 2 kg sulfur will be 2 kg only. When you burn the sulfur, it will combine with 2 kg oxygen and you will get 4 kg of sulfur bi oxide. So it is fairly close to the answer. 3 kg literally means more than 2 kg. May be you know the better answer.
The molecular weight of 1 mole of sulfur is 32 amu or grams.
(32.07/80.07)*100 =40.0%
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.
Dehydrated copper sulfate contains approximately 12.8% sulfur by weight.
Oxygen
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.
SO3
Oxygen
it is 77
Oxygen comprises about 47% by weight of Earth's crust
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
Sulfur is a non metal element. Atomic mass of it is 32.