answersLogoWhite

0


Want this question answered?

Be notified when an answer is posted

Add your answer:

Earn +20 pts
Q: What is the percent (by weight) of oxygen in sulfur trioxide (SO3)?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the percent sulfur by weight in sulfur trioxide?

(32.07/80.07)*100 =40.0%


How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?

The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)


What is the empirical formula of a compound that is 4 percent sulfur and 6 percent oxygen by weight?

We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.


What is the percent by mass of sulfur in CuSO4?

Dehydrated copper sulfate contains approximately 12.8% sulfur by weight.


By weight 65 percent of you in what element?

Oxygen


What is molecular weight of so2?

The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.


What is the empirical formula of a compound that is 40percent sulfur and 60percent oxygen by weight?

SO3


By weight 65 percent of you is what element?

Oxygen


What percent of the weight of a typical plant is oxygen?

it is 77


How many percent of oxygen comprises on weight of earths continental crust?

Oxygen comprises about 47% by weight of Earth's crust


What is the empirical formula of a compound that is 40 percent sulfur and 60 percent oxygen by weight?

We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula


What is the mass of sulfur dioxide?

Sulfur is a non metal element. Atomic mass of it is 32.