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50%
50% (apex)
Color Blindness is x-linked recessive. Therefore, it could not be heterozygous; the daughter would not be colorblind, but rather have normal vision.
Normal gametes should contain one allele from each gene.
50% probability that the sons produced from this union will be color blind. 50% probability that a son will not have the disease. 50% probability that a daughter will be a carrier of the allele for color blindness. 50% probability that a daughter will not be a carrier. Phenotypically this would be 1male color blind, 1 male not color blind, 1 female carrier and 1 female non-carrier. Assuming that the probability of male and female offspring is identical...this would be 25% of each genotype mentioned above. Based on phenotype, without regard to sex the percentages of normal to colorblind would be 75% to 25% with the 25% displaying the characteristic all being male.
codominant
codominant
A normal mouse gamete would have 19 autosomes.
codominant
Gene therapy
Gene therapy
Gene therapy