60.4
Dear Sir,I want to know that how much draw starting current of 380 volts 3 phase 50 hertz AC motors as per rating values?
50 kVA is 16.667 kVA per phase and you divide that by the phase voltage. Current = 16667 / 277 = 60 Amps
The maximum collector current is normally rated to be the current at which the DC current gain (hFE) falls to 50% of its maximum value. The maximum peak current is Page 2 Operation notes Transistors Rev.A 2/7 rated at a value which ensures reliability within the maximum allowed junction temperature.
The ratio would be a 50:1 current transformer.
Every electrical component has a rated steady state current specified at a certain ambient temperature (in most cases 40 degC). This is the "continuous" current carrying capacity of the component at the rated operating temperature. If the actual ambient tempertature in the operating area is higher than the rated ambient temperature then the "continuous" current carrying capacity of the component is reduced. This happens due to the physical property of metals which causes the resistance of the matal to increase with the increase in temperature. Example: A component rated at 8A @ 40 deg C will be rated at >7A at 50 deg C. At 50 deg C you can still pass all 8A through the component but it will genenrate more heat and can eventually burn out.
A 50 amp breaker can handle a maximum current capacity of 50 amps.
The primary current is determined by the secondary current. So, if you don't know the secondary current, you cannot work out the primary current.If the secondary isn't connected to the load, then the primary current is simply the primary voltage divided by the impedance of the primary winding.You can, though, work out the 'rated' primary current (i.e. the value of current the primary can carry, continuously). For a single-phase transformer, this will be its rated apparent power (in volt amperes) divided by its rated primary voltage. So, in this particular case, we are looking at:rated primary current = (50 x 103) / (11 x 103) = 4.55 A
The secondary current is determined by the load, not by the transformer. For example, if the secondary voltage is 50 V and the load is 100 ohms, then the secondary current will be 0.5 A. If the load is 25 ohms, then the secondary current will be 2 A. It is important that a continuous secondary current doesn't exceed the rated secondary current of the transformer.
Current (I) = Voltage (V) / Resistance (Ohms) I = V/R = 50/1000 = 50 milliamperes or 50 mA
To use an adapter of this sort, its rated voltage must match the rated voltage of the appliance, and its rated current must exceed that of the appliance. So, in your example, the rated voltage is too high to be used with your appliance.
2.5 mm twin and earth should do the trick. A 100 kw @ 400 V, 50 Hz,3 Phase at a power factor approximately 0.8 will draw a current ( 100x1000/root 3x400x0.8 )=180.42 A. Breaker rating to be 200A TP MCCB and cable size to be minimum 4 Core 120 mm2 .
Zindagi 50 50 - 2013 is rated/received certificates of: India:A Singapore:NC-16