A circuit breaker is designed to "trip" when more than its rated current passes through the breaker. The current is caused by the 120V across a load of a certain resistance. The wire conducting the current must be sized to the current. For 15 amps you need 14 gauge wire. The breaker will be labeled and will have a current and voltage rating printed on the breaker.
We know that V=IR.
This can be re-arranged for R by dividing by I. This leaves R=V/I.
Plug in the values V=120 & I=15:
R=120/15=8 ohms
R=E/I. R = 120volts / 15 amps = 8. A load of 8 ohms or less will trip a 15 amp breaker.
The resistance of a 120 volt circuit producing 15 amperes is 8 ohms.
Ohm's law: voltage = amperes * ohms
too many volts
No.
AWG # 10 wire on 30 amp circuit.
Eight on a 15 amp circuit, tweleve on a 20 amp circuit, including the gfci receptacle itself.
2.3 kw per hour on a 110-120 volt circuit.
if its a single current its 120v X 25 amp = 3000 watts
resistance = volt / current . 440 volt across a parallel circuit means the same 440 volt across both resistance s. hence resistance r = volt / current . 440 / 20 amp = 27.5 ohms total resistance
No.
No. A 120 volt 15 amp service will handle a maximum of 1,800 watts. Even a 20 amp service will only handle 2400 watts and that is at max load which you should never load on a 20 amp circuit. You will need a 30 amp 120 volt or 240 volt service for 2400 watts.
yes
AWG # 10 wire on 30 amp circuit.
It will draw over 18 amps and will blow a 15 amp fuse.
I = E / R = 120 / 14 = 8.571 Amp. (rounded)
Eight on a 15 amp circuit, tweleve on a 20 amp circuit, including the gfci receptacle itself.
2.3 kw per hour on a 110-120 volt circuit.
yes
if its a single current its 120v X 25 amp = 3000 watts
The current is half an amp because amps times volts equals watts.