9 ohms
Potential Difference across a resistor is given by, Potential Difference = Resistance * Current = 1500 * 0.075 = 112.5 Volts
Resistance (Ohms) = Potential Difference (Volts) / Current (Amps) So, 12/0.25 = 48 Ohms.
Your question reveals fundamental misunderstandings about the nature of electricity.'Voltage' is simply another word for 'potential difference', and a potential difference appears across opposite ends of the resistor; it doesn't 'travel through' that resistor! Current, on the other hand, DOES 'travel through' the resistor and is caused by the potential difference across the resistor.Resistance is the ratio of potential difference to current. So if the resistance remians unchanged when the current through it doubles, then it has happened because the potential difference has doubled.
Potential difference equals current multiplied by resistance or E = IR therefore the answer to your question is 25 volts
A resistor's resistance is measured in ohms. The higher the resistance the less current will flow with a constant voltage applied across the resistor. In terms of Ohm's Law Voltage = Current x Resistance.
You can measure it, but you can't calculate it. That's why the resistance of a resistor is always printed on it, either in numbers or in color bands. Without that marking, the resistor is pretty useless. If it accidentally missed being marked during manufacture, it would be either discarded, or sold surplus for bubkes.
Use Ohm's Law, i.e., V=IR here, V=voltage I=current R=resistance
The voltage of a battery goes as the current times the resistance (V=IR). Because the voltage is being held constant, the resistor that draws the most current will have the lower resistance.
IF there is a Resistor
Using ohm's law, V=IR then R=V/I =6/0.0015=4000 ohm = 4k ohm resistor.
A ballast resistor is an electrical resistor whose resistance varies with the current passing through it, thus maintaining a constant current.
V=I*R -- Potential (Voltage, V) = Current (Amperage, I) * Resistance (Ohms)2A*5Ohms = 10V