There is insufficient information to properly answer this question. The answer provided attempts to provide insight, but the answer is incomplete.
A 12V, 150AH battery will put out 2250 watts for eight hours, give or take a little. A naive answer would say that the running time is 2250 divided by 600, or 3.75 hours. There are, however, several factors that need to be considered...
The ampere-hour rating of the battery is non linear. It is normalized to a eight-hour rate. It appears that the running time is more than 3.75 hours.
The battery voltage will decrease over time, and the rating is based on amperes, not on watts. It appears that the running time is less than 3.75 hours.
The minimum input voltage rating of the inverter, and the maximum voltage rating of the battery at full discharge were not specified. It appears that the running time is less than 3.75 hours.
The overhead, or inefficiency, of the inverter was not specified, so not all of that 600W is available to the load. It appears that the running time is less than 3.75 hours.
The power factor of the inverter and of the load was not specified. The running time difference in this aspect is not known.
The thermal rating and maximum run time of the inverter was not specified. The running time difference in this aspect is not known.
A half bridge inverter is an electronic circuit that uses different phases to do what it needs to do. A full bridge inverter is a single phase device so a half bridge is more complicated than a full bridge.
battery backup is fully depended on battery discharge characteristics. discharge characteristics are c1 c5 c20 Need to consider c factor, calculating backup of batteries 100 AH BATTERY DISCHARGED BY 5 AMP CONSTANT = 100 AH 100 AH BATTERY DISCHARGED BY 20 AMP CONSTANT= 85 AH 100 AH BATTERY DISCHARGED BY 50 AMP CONSTANT=70AH 100 AH BATTERY DISCHARGED BY 100 AMP CONSTANT=50AH FOR KIND CONSIDERATION. FOR ANY CLARIFICATION CONTACT saalsood@gmail.com Battery back up time=Battery current at full load/Battery Ah
FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
Approximately 746 watts of usuable power are equivalent to 1 horsepower. A 1hp motor, under full load, will draw more than 746 watts due to the inherent losses in the motor itself.
The question has to be more specific. Full load amps, watts or voltage. Please restate your question.
The frequency inverter changes the frequency of power lines to the electric motor, hence to change the speed of the motor, in some applications like conveyor, it does not need full speed running all the times, so the frequency inverter comes in as the speed control role to save electric energy.
A half bridge inverter is an electronic circuit that uses different phases to do what it needs to do. A full bridge inverter is a single phase device so a half bridge is more complicated than a full bridge.
Power (P), in Watts, is equal to the Voltage (V), in Volts, multiplied by the Current (I), in Amperes. P=V*I Using Algebra to solve for the Current (Amps) that are required: I=P/V Therefore: 2000 Watts / 12 Volts = ~167 Amps Please note, that this is for a 100% efficient inverter. If the inverter is 90% efficient the actual draw would be: Iideal*(1+(1-(%Efficiency/100)))=Iactual 167 Amps*(1+(1-(90/100)))=Iactual 167 A * (1+(1-0.9))=Iactual 167 A * (1+(0.1))=Iactual 167 A * (1.1)=Iactual 183 A = Iactual The continuous current draw for a 90% efficient power inverter, operating from a 12V DC source, out putting 2000W at 120V AC, is 183 Amps.
A 24Whr battery lasts 24hr if the system is using 1 Watts/hr. So it depends on how many watts the system uses. Typical netbooks may use about 30watts/hr so you may get about an hr on a full charge....
battery backup is fully depended on battery discharge characteristics. discharge characteristics are c1 c5 c20 Need to consider c factor, calculating backup of batteries 100 AH BATTERY DISCHARGED BY 5 AMP CONSTANT = 100 AH 100 AH BATTERY DISCHARGED BY 20 AMP CONSTANT= 85 AH 100 AH BATTERY DISCHARGED BY 50 AMP CONSTANT=70AH 100 AH BATTERY DISCHARGED BY 100 AMP CONSTANT=50AH FOR KIND CONSIDERATION. FOR ANY CLARIFICATION CONTACT saalsood@gmail.com Battery back up time=Battery current at full load/Battery Ah
Weak battery not holding a full charge or alternator not supplying a suffient charge to the battery - check with a voltmeter A fully charged battery should read approx. 12.8 without engine running Approx. 13.8-14.2 with engine running
Depends. An older Diesel is likely to keep running. A modern, with a full set of electronic engine diagnostic might not.
An ordinary kitchen fidge uses about 100 watts when the motor is running, which is for about 2-3 minutes each hour unless the door is opened a lot. When the fridge is full it uses less energy because less warm air enters each time the door is opened.
Because the weed eater gets its power from the battery, not the charging unit. The charging unit most likely does not have enough amps to run the unit, whereas the battery does after a full charge.
FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
Theirs a battery on the bottom right screen.If it full then that means the battery's fully charged.
At low volume you could get away with a much lower watt inverter, however, if you intend to use more it would be better to have the full range at your disposal. Peak output power for one of those is typically around 2400w, but be aware that it will generate some heat in use so locate it in a good area with airflow.