As you don't specify how R1 & R2 are connected, it is impossible to give an answer to your question.
thanks to ohm,,who invented the answer.according ohms law,V voltage=R(element)xI amps.then.....answer is....100 volts.
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
6.6 kV and 11 kV refer to the voltage rating of the fuse. 160A refers to the current rating. The 6.6 kV fuse is safe to use in a circuit with a voltage up to 6.6 kV and no greater. The 11 kV fuse is safe to use in a circuit with a voltage up to 11 kV.
The current in a reading lamp would be a small part of the total current in a home. For example, a home may have 100 amp service, while a reading light may draw less than 1 amp, so about 1% of the total.
1). You don't need the voltage 'E' in order to calculate the total resistance. The totalresistance is the same whether the circuit is connected to a big battery, to a smallbattery, to a bicycle pump, or lying in the back of the desk drawer.2). In a series circuit, the total resistance is just the sum of the individual resistances.In this example, the total resistance isR1 + R2 + R3 = 100 + 500 + 600 = 1,200 ohms .
A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms. The current flow in the circuit is 100v/1000ohms which would equal .1.
Percentage reactance of a transformer (or in general, a circuit) is the percentage of phase voltage drop when full load current flows through it, i.e %X=(IX/V)*100. Now Short Circuit Current is V/X So short Circuit current is I*(100/%X).
Percentage reactance of a transformer (or in general, a circuit) is the percentage of phase voltage drop when full load current flows through it, i.e %X=(IX/V)*100. Now Short Circuit Current is V/X So short Circuit current is I*(100/%X).
when A resistance is connected across the supply voltage, total input vooltage will be drop in the resistance when the resistances are connected across the supply voltage, total input vooltage will be devidedacross the resistances. IF R value will be high ,drop also high. IF R value wll be low ,voltage drop will be less.
thanks to ohm,,who invented the answer.according ohms law,V voltage=R(element)xI amps.then.....answer is....100 volts.
To answer this question, you need to know how many amps the circuit that is connected to the light bulb can handle. For home applications with a 15 amp circuit and no other loads connected you get: Power = Current * voltage, Substituting the known information yields: power = 15 amps * 110 volts, which is 1650 watts of total capacity. You have 100 watt bulbs, so: 1650/100 = 16.5 bulbs If your circuit is other than 15 amps, or if there is additional loads on the circuit, you must adjust the current or total capacity accordingly
To find the current running through the circuit, you need to use Ohm's Law, which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. You can use the following formula to calculate the current: I = V / R Where I is the current, V is the voltage, and R is the resistance. In this case, the total resistance of the circuit is the sum of the individual resistances, which is 5 ohms + 20 ohms + 25 ohms = 50 ohms. Therefore, the current flowing through the circuit is: I = 100 volts / 50 ohms = 2 amps.
The breakdown voltage of a diode is the minimum voltage at which it conducts in both directions. If you have a 100-volt rectifier diode (1N4002) and you wire it into a 110v circuit, it will flow current in both directions and you'll get no rectification.
A 120V household electrical outlet supplies 12 watts of powerwhen the current is 0.1 Ampere (and the power factor is 100%).
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
If a secondary voltage is given across a particular resistive load in a series of known resistive loads, multiply the voltage by the ratio of the total load to the measures load to get total voltage. Example: You have a series of a 200 ohm resistor to a 100 ohm resistor. The votage measured across the 100 ohm is 2 volts. 200 + 100 = 300. 300 / 100 = 3. 2 X 3 = 6. Total Voltage in the circuit is 6V
Well, voltage and current levels being identical, alternating current would be safer. It does not spend 100 percent of its time at peak voltage, therefore the average power in case of an electric shock is lower than that of direct current, which is 100 percent. This lesser average may allow some time to detach from the circuit and may not cause such catastrophe to the body.