The answer is 0,526 mL.
You need 10 moles of acid (980,79 g).
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
The concentration in moles of a substance in the solution
I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1
The molarity of a solution containing 7.0 moles of solute in 569mL of solution is a)81M b)0.081M c)12M D)4.0M The answer is C. 12M 7 x 1000/569 = 12.302
0.9051 moles Mg per liter of solution. Molarity is the amount of moles per liter of solution. So just divide the number of grams of Mg by its molar mass then divide that by the number of liters
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
The concentration in moles of a substance in the solution
To calculate the number of milliliters (mL) of hydrochloric acid (HCl) required to prepare a standard solution of 2 mols of HCl, we need to know the concentration of the available HCl solution. The calculation involves the following steps: Determine the number of moles of HCl desired in the solution. Given: 2 mols of HCl Determine the concentration (molarity) of the available HCl solution. Let's assume the concentration is 6 M (This is a common concentration for laboratory-grade HCl, but you should use the actual concentration of your solution). Use the molarity equation to calculate the required volume (in liters): Molarity (M) = moles of solute / liters of solution 6 M = 2 mols / liters of solution Liters of solution = 2 mols / 6 M Liters of solution = 0.333 L Convert the volume from liters to milliliters: Volume in mL = Volume in liters × 1000 mL/L Volume in mL = 0.333 L × 1000 mL/L Volume in mL = 333 mL Therefore, to prepare a standard solution of 2 mols of HCl using a 6 M HCl solution, you would need approximately 333 mL of the concentrated HCl solution. Note: The actual volume may vary slightly depending on the precise concentration of the HCl solution you are using and any significant figures involved in the calculation.
Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.
This the molarity.
I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
Molarity = number of moles / number of liters. For this question the number of moles is 3 and the number of liters is 0.5 So 3/0.5 = 6 The solution is 6 M.
Molarity means the number of mol of a substance per 1 litre of substance. Or figure out the number of mol of NaCl ((2.60/(23+35)=0.04) then multiply the 35ml by 28.571428 to get that to litres.. then multiply the number of mol by 28.571428 to get that to the number of mol. Therefore the answer is 1.142857M. See the Related Questions link "How do you prepare a solution of a specific concentration?"
first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.
Moles of solute ---------------- Liters of solution So, convert your grams to moles by dividing by the molar mass (add together the atomic masses of the solution) and then that will give you your moles. Divide that number by your 6.3 Liters. That number is your molarity.