We know that sodium is atomic number 11, and it has 11 protons, 11 electrons (in a neutral atom), and will have 12 neutrons in its sodium-23 isotope. Sulfur is atomic number 16, and will have 16 protons, 16 electrons (in a neutral atom), and will have 16 neutrons in it sulfur-32 isotope. Oxygen has atomic number 8, and has 8 protons, 8 electrons (in a neutral atom) and will have 8 neutrons in its oxygen 16 isotope. If we take 2 sodium atoms, a sulfur atom and 4 oxygen atoms, we'll have a total of 70 protons, 72 neutrons and 70 electrons in sum.
The number of protons and electrons is 70; the number of neutrons depends on the isotopes of S and O.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).
Because Na2SO4 is an ionic compound and so does not have actual molecules.
Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq).
2(11) + 16 + 4(8) = 70
Sulfate consists of 1 S, and 4 O and so has a charge of 2-. You can see this directly from the periodic table by checking what group these atoms are in. Sulfur and Oxygen are both in the 6th group, meaning they both have 6 valence electrons. So (6 electrons * 5 atoms) = 30 electrons. If we follow the octet rule (each atom must have 8 valence electrons for a full octet), then we need 2 more electrons. Sodium, Na, is in the 1st group on the periodic table, and therefore has 1 valence electron. So we need 2 sodium atoms, giving us the formula: Na2SO4 That is, 2 Na 1 S 4 O It's important to remember that when atoms 'share' their electrons by bonding, that BOTH atoms 'see' the electrons as theirs, meaning that, for example, although you may have 14 electrons between 2 atoms, as long as there is a single bond between the atoms they will both have full octets. For example: O2 :::O:O::: where : = pair of electrons.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).
Na2SO4(s) --> 2Na+(aq) + SO4-2(aq)
1 mol Na2SO4 will dissociate to 2 mol Na+ and 1 mol SO42- Therefore 0.350 M Na2SO4 will dissociate to 0.350*2 = 0.700 mol Na+ and 0.350*1 = 0.350 mol SO42- Therefore the total concentration of ions is 0.700 mol + 0.350 mol = 1.050 mol.
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
Because Na2SO4 is an ionic compound and so does not have actual molecules.
Na2SO4 and NaCl
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
Assuming you have a "+" sign in between the two reactants, this represents a single replacement reaction. They products will be Mg and Na2SO4.