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For this problem you have to use PV=nRT.

In order to get anywhere with the question, you have to isolate the V (volume) and get it alone. To do that, you have to divide each side by P (pressure). When you do that, your new formula to work with is:

V = nRT / P

(the P cancelled out on the other side, which left you with V)

Unfortunately, you weren't given the number of moles in the problem. Instead, they made it a bit more challenging by giving you the number of grams, which can be converted to give you your number of moles:

42 g / 1 ( 1 mole / 28.01 g) = 1.5 moles of CO

Now, you have all the information that you need in order to answer the question. All you have to do now is plug in, but make sure that you know where everything goes:

n (moles) = 1.5 moles

R = .0821 L atm / mole K <-----that one looks weird, but that's all required for R

T (temp) = 273 K <----that's your standard temp *must be in Kelvin!!!! ALWAYS!!

P (pressure) = 1 atm <----standard pressure for P *must be in atm!! ALWAYS!!

Your equation should now look like this:

V= (1.5 moles x .0821 Latm/ moleK x 273 K) / (1 atm) =

34 L CO

And then you get your answer!

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12y ago
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6d ago

At Standard Temperature and Pressure (STP), the volume occupied by 1 mole of any gas is 22.4 L. Since CO2 has a molar mass of approximately 44 g/mol, 132g of CO2 would be equivalent to 3 moles. Therefore, the total volume occupied by 132g of CO2 at STP would be 3 moles * 22.4 L/mole = 67.2 L.

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9y ago

Vstp = ( n ) ( 22.42 L/mol ) = ( m/M ) ( 22.42 L/mol )

Vstp = ( 92.31 g / 44.01 g per mol ) ( 22.42 L per mol at STP )

Vstp = ( 2.097 mol ) ( 22.42 L/mol )

Vstp = 47.03 L <-----[ Answer ]

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8y ago

The volume is 46,69 L.

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8y ago

The volume is 66,77 mL.

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11y ago

2.24 L

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11y ago

8.96 cm3

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Q: What is the total volume occupied by 132g of CO2 at STP?
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What is the volume in milliliters occupied by 89.2g CO2(g) at 37oC and 737 mmHg?

To find the volume of a gas using the ideal gas law formula PV = nRT, we need to know the molar mass of CO2 (44.01 g/mol) and convert grams to moles. Then we can rearrange the formula to solve for V (volume) using P (pressure), n (moles), R (gas constant), and T (temperature). After plugging in the values (P = 737 mmHg, T = 37°C + 273 = 310 K), we can calculate the volume occupied by 89.2g of CO2 gas.


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What volume does 22g of CO2 at STP occupy?

22g of CO2 at STP (standard temperature and pressure) is equivalent to 1 mole. The volume occupied by 1 mole of any gas at STP is approximately 22.4 liters.


What is the volume of a sample of co2 at stp that has a volume of 75.0 ml at 30.0c and 91 kpa?

To calculate the volume of CO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. First, find the number of moles of CO2 using the ideal gas law equation. Then, use the molar volume of a gas at STP (22.4 L/mol) to find the volume at STP.


How many grams does 3 moles of CO2 weigh?

Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g

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What is the volume in milliliters occupied by 89.2g CO2(g) at 37oC and 737 mmHg?

To find the volume of a gas using the ideal gas law formula PV = nRT, we need to know the molar mass of CO2 (44.01 g/mol) and convert grams to moles. Then we can rearrange the formula to solve for V (volume) using P (pressure), n (moles), R (gas constant), and T (temperature). After plugging in the values (P = 737 mmHg, T = 37°C + 273 = 310 K), we can calculate the volume occupied by 89.2g of CO2 gas.


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What is the volume of a sample of co2 at stp that has a volume of 75.0 ml at 30.0c and 91 kpa?

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How many grams does 3 moles of CO2 weigh?

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