The volume is 3,81 L.
This is another calculation. there are 0.123 moles inn this volume.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
what is the volume of a balloon containing 50.0 moles of O2 gas at a pressure of 15.0 atm at 28 degrees
The answer is 0,125 moles.
Pressure, volume and temperature, and moles of gas are the four principal variables to describe a gas (for example, see related questions on Ideal Gas Law and others). The standard units are: Pressure: atmospheres (atm) Volume: liters (L) Temperature: Kelvin (K) Number of moles are measure in, well, moles.
38 L
38 L
This is another calculation. there are 0.123 moles inn this volume.
The volume is 13,64 L.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
38 L
what is the volume of a balloon containing 50.0 moles of O2 gas at a pressure of 15.0 atm at 28 degrees
340.89 k
I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation. PV = nRT (1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K) Volume = 59 Liters of chlorine gas --------------------------------------------
The partial pressure of the hydrogen will be 0.853 atmospheres.
0.125 moles
The answer is 0,125 moles.