120v
The correct question is what is the voltage drop across a resistor or the current flowing through the resistor using Ohm's Law where Voltage = Current x Resistance
The question is incomplete without the voltage across the resistor. For example: if V (Voltage across 500 ohm resistor) = 5 Volts, then, Current, I = 5/500 Ampere = 0.01 A.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).
The voltage must reduce by the same factor - that is Ohm's law.
Two milliamperes. Ohm's law: Current equals voltage divided by resistance.
A resistor's resistance is measured in ohms. The higher the resistance the less current will flow with a constant voltage applied across the resistor. In terms of Ohm's Law Voltage = Current x Resistance.
The 5 Ohm resistor will have more current passing through it than the 10 ohm resistor. Since the resistors are in parallel the Voltage across each resistor is the same. Power or the amount of heat in terms of the question can be derived from Power = Voltage * Current. Ohm's law tells us that the current flowing through a resistor is equal to the Voltage across the resistor divided by the resistance. The formula for power is then the Voltage * Voltage / Resistance. Since V^2 / 10 is smaller than V^2 / 5 we know that the 5 ohm resistor will always have more power dissipated than the 10 ohm resistor.
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
Not enough information. But if you know the current, you can use Ohm's Law (just multiply the resistance times the current).
Voltage / Resistance = Current, you do the math
The resistor is 1/3 of an ohm. A 9 volt drop across the resistor would cause a draw of 27 amps through the resistor. The wattage you would need for that resistor is at least a 243 watts.