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What is voltage across the 6.7 ohm resistor in series circuit with 23.7 V battery and resistors of 22.7ohms 39.3ohms and 6.7ohms?
Reconzrt
hey!! let's see how we can figure this out, cool?!
let's label some things first.
Vbattery = 23.7 V
R1 = 22.7 ohms
R2 = 39.3 ohms
R3 = 6.70 ohms
here's a little diagram..
GND-------[- Vbattery +]-----------[ R1 ]-------[ R2 ] -------[ R3 ]-----------GND
current, I, will be flowing through this circuit.
but which way?
current flows out of the + part of the battery.
so real fast, let's add something to the diagram, cool?
I
------------>
GND-------[- Vbattery +]-----------[ R1 ]-------[ R2 ] -------[ R3 ]-----------GND
I
<------------
all the elements are in series, will there be a constant current or constant voltage?!
you're right !! there's a different voltage drop at each resistor, so the current must be the same throughout the entire circuit. i kept drawing the voltage drops, but the picture is busted when saved. =(
k, let's ask that dead guy, mr. ohms, for his equation.. k, cool, it's V = I x R.
(1) solve for I
I = V/R = Vbattery/(R1 + R2 + R3) = 23.7V/68.7ohms = 0.33498 A
= 0.33498 A x 1000
= 334.98 mA
(2) solve for VR3 - voltage (drop) across 6.7 ohm resistor
VR3 = I x R3 = 2.31 V < ur answer.
(3) check
VR1 = I x R1 = 7.83 V
VR2 = I x R2 = 13.56 V
VRtotal = VR1 + VR2 + VR3 = 23.7 = Vbattery !!
yay.
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