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In 1 litre (L) there are 2 moles (M)
So in 2.5 L you have 2.5 X 2 = 5 moles.
Remember the moles eq'n
moles = mass(g) / Mr
Hence mass(g) = moles X Mr
Next refer to the Periodic Table in order to find the atomic masses of the atoms in sodium sulphate (Na2SO4)
Na x 2 = 23 X 2 =46
S x 1 = 32 X 1 = 32
O x 4 = 16 X 4 = 64
46 + 32 + 64 = 142 ( The Mr of sodium sulphate).
Substituting into the equation
mass(g) = 5 moles X 142(Mr)
mass(g) = 710 g is required.
To make at a practical level.
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have approximately 1.5 litres of water .
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dissolve the whole mass of sodium sulphate (710 g) in this quantity of water.
You will notice that the volume of the solution increases.
- Then add sufficient water to make a total volume of 2.5 litres.
NB Do NOT add the sodium sulphate to 2.5 litres. Because then you will have more volume of less molarity .
What else can I help you with?
What is the mass of Na2SO4 needed to make 2.5 L of 2.0 M solution?
how man molecules are there in 450 grams of Na2SO4. the simple formula to determine of mole is NO OF MOL= GIVEN MASS IN gm/MOL:MASS OF COMP: , AND IMOL = 6.02X1023 . SO, 19. 077X1023 molecules are present in 450 grams of Na2SO4.
How many grams of Na2SO4 are required to make 350 ml of 0.5M?
To find the grams of Na2SO4 needed, you first need to calculate the number of moles using the molarity formula: moles = Molarity x Volume (in liters). Then, use the molar mass of Na2SO4 (142.04 g/mol) to convert moles to grams. In this case, you would need 35.25 grams of Na2SO4 to make 350 ml of 0.5M solution.
How many moles are in Na2SO4?
To determine the number of moles in Na2SO4, you first need to know the molar mass of the compound. The molar mass of Na2SO4 (sodium sulfate) is calculated by adding the atomic masses of each element present: 2(Na) + 1(S) + 4(O) = 2(22.99 g/mol) + 1(32.07 g/mol) + 4(16.00 g/mol) = 142.04 g/mol. To find the number of moles, you divide the given mass of Na2SO4 by its molar mass.
What is the total number of grams of NaI(s) needed to make 1 L of a 0.010M solution?
To make a 0.010M NaI solution, you'll need 0.010 moles of NaI per liter. The molar mass of NaI is 149.89 g/mol. Therefore, to calculate the grams needed, you would multiply the molar mass by the number of moles, which gives you 1.499 g of NaI needed per liter of solution.
When calculating the mass of borax needed to make up a standard solutiondo you ionclude 10h2o?
No, when calculating the mass of borax needed to make a standard solution, you do not include the water of hydration (such as the 10H2O). You only consider the anhydrous borax (without water molecules) in your calculations.
What is the mass of Na2SO4 needed to make 2.5 L of 2.0 M solution?
how man molecules are there in 450 grams of Na2SO4. the simple formula to determine of mole is NO OF MOL= GIVEN MASS IN gm/MOL:MASS OF COMP: , AND IMOL = 6.02X1023 . SO, 19. 077X1023 molecules are present in 450 grams of Na2SO4.
If 57.0 mL of BaCl2 solution is needed to precipitate all the sulfate ion in a 742 mg sample of Na2SO4 what is the molarity of the solution?
To find the molarity of the BaCl2 solution, first calculate the moles of Na2SO4 in the sample using its molar mass. Then, use the balanced chemical equation of the precipitation reaction to determine the moles of BaCl2 needed to react with the moles of Na2SO4. Finally, divide the moles of BaCl2 by the volume of the solution in liters (57.0 mL = 0.057 L) to find the molarity.
How many grams of Na2SO4 are required to make 350 ml of 0.5M?
To find the grams of Na2SO4 needed, you first need to calculate the number of moles using the molarity formula: moles = Molarity x Volume (in liters). Then, use the molar mass of Na2SO4 (142.04 g/mol) to convert moles to grams. In this case, you would need 35.25 grams of Na2SO4 to make 350 ml of 0.5M solution.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution?
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
What mass of water must be added to 255.0g NaCl to make a 15.00 percent by mass aqueous solution?
To make a 15.00% by mass aqueous solution with NaCl, the mass of NaCl is 255.0g. This means that 15.00g of NaCl is present in every 100.00g of solution. To find the mass of water needed, first calculate the mass of NaCl in the final solution, then subtract this amount from the total mass of the solution (water + NaCl).
How many moles of Na SO4 are in 25.0 of this compound?
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
How many moles are in Na2SO4?
To determine the number of moles in Na2SO4, you first need to know the molar mass of the compound. The molar mass of Na2SO4 (sodium sulfate) is calculated by adding the atomic masses of each element present: 2(Na) + 1(S) + 4(O) = 2(22.99 g/mol) + 1(32.07 g/mol) + 4(16.00 g/mol) = 142.04 g/mol. To find the number of moles, you divide the given mass of Na2SO4 by its molar mass.
When you calculate the mass of borax needed to make up the standard solution do you include 10H2O?
No, when calculating the mass of borax needed for a standard solution, you only consider the anhydrous (water-free) form of the compound. The water molecules incorporated in the crystal structure are not included in the calculation of the mass.
How would you determine the mass of SO4 ions in 4.5g of NA2SO4?
To determine the mass of SO4 ions in 4.5g of Na2SO4, first calculate the molar mass of Na2SO4 (which is 142.04 g/mol). Next, find the molar mass ratio of SO4 in Na2SO4 (which is 96.06 g/mol out of 142.04 g/mol). Finally, calculate the mass of SO4 ions by multiplying the molar mass ratio by the total mass of Na2SO4 (4.5g).
Mass of Na2SO4 that contains 3.011023 formula units?
This mass is 72,02 g.
How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
What is the total number of grams of NaI(s) needed to make 1 L of a 0.010M solution?
To make a 0.010M NaI solution, you'll need 0.010 moles of NaI per liter. The molar mass of NaI is 149.89 g/mol. Therefore, to calculate the grams needed, you would multiply the molar mass by the number of moles, which gives you 1.499 g of NaI needed per liter of solution.
