To determine the number of moles in Na2SO4, you first need to know the molar mass of the compound. The molar mass of Na2SO4 (sodium sulfate) is calculated by adding the atomic masses of each element present: 2(Na) + 1(S) + 4(O) = 2(22.99 g/mol) + 1(32.07 g/mol) + 4(16.00 g/mol) = 142.04 g/mol. To find the number of moles, you divide the given mass of Na2SO4 by its molar mass.
There are 10.5 moles of sodium in 5.25 moles of Na2SO4 because there are 2 sodium atoms in one formula unit of Na2SO4.
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
The answer is approx. 2 moles (for anhydrous sodium sulfate).
To find the volume of 0.24M Na2SO4 oxidized by 0.32 kmno4, first calculate the number of moles of KMnO4 using the formula M1V1 = M2V2. Then, use the mole ratio between KMnO4 and Na2SO4 (from the balanced equation) to find the moles of Na2SO4 oxidized. Finally, convert the moles of Na2SO4 to volume using its molarity.
The balanced chemical equation for the reaction is: H2SO4 + 2NaOH -> Na2SO4 + 2H2O. To find the amount of Na2SO4 produced, first find the limiting reactant by calculating the moles of each reactant. Then, use the mole ratio from the balanced equation to determine the moles of Na2SO4 produced. Finally, convert moles to grams using the molar mass of Na2SO4 to find the final amount.
There are 10.5 moles of sodium in 5.25 moles of Na2SO4 because there are 2 sodium atoms in one formula unit of Na2SO4.
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
To find the grams of sodium in 0.820 moles of Na2SO4, first calculate the molar mass of Na2SO4: 2(Na) + 1(S) + 4(O) = 2(23) + 32 + 4(16) = 142 g/mol. Since each mole of Na2SO4 contains 2 moles of Na atoms, the molar mass of Na in Na2SO4 is 46 g/mol. Therefore, in 0.820 moles of Na2SO4, there are 0.820 moles * 2 moles Na * 46 g/mol = 75.32 grams of sodium.
The answer is approx. 2 moles (for anhydrous sodium sulfate).
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
To find the volume of 0.24M Na2SO4 oxidized by 0.32 kmno4, first calculate the number of moles of KMnO4 using the formula M1V1 = M2V2. Then, use the mole ratio between KMnO4 and Na2SO4 (from the balanced equation) to find the moles of Na2SO4 oxidized. Finally, convert the moles of Na2SO4 to volume using its molarity.
There are approximately (1.93 \times 10^{24}) atoms in 3.2 moles of Na2SO4. This value is calculated using Avogadro's number (6.022 x 10^23 atoms/mol) and the formula weight of Na2SO4.
There are 0.850 moles of Na2SO4 in 325 mL of 0.850 M solution. Since Na2SO4 contains 2 sodium ions per formula unit, there will be 2*0.850 moles of sodium ions in the solution. Thus, there are 1.7 moles of sodium ions in 325 mL of 0.850 M Na2SO4 solution.