142 grams Cl2 Thank Yhuung Marker FB <---
142 grams Cl2
It means 14% of the molecules of the sodium Hypochlorite solution contain the "free-chlorine" required to actually do the desired job of the Hypochlorite. Effectively, only 14% of the mass or moles of the Hypochlorite will react.
The atomic ratio in this salt is 1:1. The mass ratio is 22.999:35.457 of sodium to chlorine, the ratio of the atomic weights of sodium and chlorine.
The equation for the reaction between sodium and chlorine is 2 Na + Cl2 -> 2 NaCl. This equation shows that equal numbers of formula units of sodium and chlorine are changed during the reaction. The gram atomic mass of two sodium atoms is 2 [exact] X 22.9898 or45.9796. therefore the specified amount of sodium is 92.0/45.9796 or 2.00 double gram atoms, to the justified number of significant digits. Therefore 2.00 double gram atoms of chlorine are required. The gram atomic mass of chlorine is 35.453, and four times this amount, or 142 grams of chlorine, to the justified number of significant digits, are needed for complete reaction.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
The percentage of sodium in sodium chloride is 39,665 83 %. Mass of NaCl = Mass of sodium X 2,51
142 grams Cl2
The ratio mass of chlorine/mass of sodium is 1,5.
By atoms it is 50% sodium and 50% chlorine. By mass (sodium is 23.0, chlorine is 35.5, salt is 58.5) is 39.3% sodium and 60.7% chlorine.
It means 14% of the molecules of the sodium Hypochlorite solution contain the "free-chlorine" required to actually do the desired job of the Hypochlorite. Effectively, only 14% of the mass or moles of the Hypochlorite will react.
5.0 grams.
The atomic ratio in this salt is 1:1. The mass ratio is 22.999:35.457 of sodium to chlorine, the ratio of the atomic weights of sodium and chlorine.
The equation for the reaction between sodium and chlorine is 2 Na + Cl2 -> 2 NaCl. This equation shows that equal numbers of formula units of sodium and chlorine are changed during the reaction. The gram Atomic Mass of two sodium atoms is 2 [exact] X 22.9898 or45.9796. therefore the specified amount of sodium is 92.0/45.9796 or 2.00 double gram atoms, to the justified number of significant digits. Therefore 2.00 double gram atoms of chlorine are required. The gram atomic mass of chlorine is 35.453, and four times this amount, or 142 grams of chlorine, to the justified number of significant digits, are needed for complete reaction.
The equation for the reaction between sodium and chlorine is 2 Na + Cl2 -> 2 NaCl. This equation shows that equal numbers of formula units of sodium and chlorine are changed during the reaction. The gram atomic mass of two sodium atoms is 2 [exact] X 22.9898 or45.9796. therefore the specified amount of sodium is 92.0/45.9796 or 2.00 double gram atoms, to the justified number of significant digits. Therefore 2.00 double gram atoms of chlorine are required. The gram atomic mass of chlorine is 35.453, and four times this amount, or 142 grams of chlorine, to the justified number of significant digits, are needed for complete reaction.
50 g sodium chloride (NaCl) contain 30,167 g chlorine.
The chemical reaction is:AgNO3 + NaCl= AgCl + NaNO3The mass of products depends on the mass of reactants.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.