What_mass_of_potassium_ions_is_present_25.0_mL_of_0.50_M_K2SO4
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Two potassium ions. 2K(+) and One polyatomic ion of sulfate SO4(2-)
Barium chloride solution: Ba2+ and Cl-. Potassium sulfate: K+ and (SO4)2-.
In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+
9.03x10 23 ions
3(2.6) = 7.8 moles of ions
Two potassium ions. 2K(+) and One polyatomic ion of sulfate SO4(2-)
Multiple the moles of K2SO4 by the molecular weight of 174.2592 grams. That should equal 210.85 grams.
The symbol for potassium sulphate is K2SO4 . It contains K+ and SO42- ions.
Barium chloride solution: Ba2+ and Cl-. Potassium sulfate: K+ and (SO4)2-.
The Calculation25ml = 0.025dm30.5M = 0.5 moles per dm30.5 mol dm-3 x 0.025dm3 = 0.0125 moles of K2SO4Which equals 0.01125 moles of KThis in grams is 0.01125 x 39.098 (the molar mass of potassium) = 0.4398525g
In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+
9.03x10 23 ions
Since the product, K2SO4 has twice as many potassium atoms as the reactant, KNO3, we may conclude that it takes two moles of reactant to produce one mole of product. The sulfate and nitrate ions will not be the limiting factor.
3(2.6) = 7.8 moles of ions
Potassium hydroxide is an ionic lattice. It has two types of ions and namely they are potassium ions and hydroxyl ions.
Get a wire. Bend it into a ring and put a few crystals of your solid on it. Do a flame test using a Bunsen burner. Potassium will give a violet flame and Sodium ions will give a Yellow flame.
3 sodium ions for 2 potassium ions.