One to one (or two to two, which is the same as one to one).
The chemical equation is as follows: 2NaHCO3 -----> Na2CO3 + CO2 + H2O. Note that the ratio of moles of CO2 produced to moles of NaHCO3 reacted is 1:2.
there are 2 moles of Hcl needed to produce 1 mole of carbon dioxide
NaHCO3 + HCl(aq) -> NaCl(aq) + H2CO3
1 mole NaHCO3/1 mole NaCl
and vice versa
The short answer is one
I mole.
The reaction is
2NaOH + CO2 -> Na2CO3 +H2O
1 : 1 : 1 : 1
1:1
Let's see.2NaOH + H2CO3 --> Na2CO3 + 2H2OSodium carbonate is the salt. Though carbonic acid is a weak acid and a one to one mole ratio may not achieve this ideal reaction.
0.01 mole
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
The mole ration is 1:1
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
try to understand the question first
It depends on what it is reacting with.
Let's see.2NaOH + H2CO3 --> Na2CO3 + 2H2OSodium carbonate is the salt. Though carbonic acid is a weak acid and a one to one mole ratio may not achieve this ideal reaction.
0.01 mole
The formula is: NaOH(aq) + HCl(aq) --> NaCl + H2O(l) So the ratio is: 1 : 1 : 1 : 1
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
The mole ration is 1:1
Use simple stoichiometry, with .6 grams of the calcium carbonate corresponding to a mole to mole ratio of 2:1 Acid:base
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
the experimental mole ratio has a bigger penis
Generally, if you increase a reagent and there is no increase in the reaction, then it is limited by the amount of another reagent present. For example, a mole of Sodium Hydrogen Carbonate will react with a mole of Acetic Acid. However, doubling the Acetic acid will not result in a greater reaction because it is limited by the amount of Sodium Hydrogen Carbonate present.