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What the time periods of a simple pendulum at equator of the earth?
Wiki User
∙ 9y ago
For small swings of a mass suspended on a weightless string, the period is given by T = 2 pi sqrt (a/g) where a is the length of the pendulum and g is the acceleration due to gravity.
Wiki User
∙ 9y ago
The time period of a simple pendulum at the equator of the Earth is slightly longer than at other latitudes due to the centrifugal force from the Earth's rotation. This force decreases the gravitational force experienced by the pendulum, leading to a longer period. The difference in period between the equator and other latitudes is very small, however, and not easily noticeable in everyday practice.
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What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
Can you conduct simple pendulum experiment at the centre of the earth?
It would not be possible to conduct a simple pendulum experiment at the center of the Earth due to extreme heat and pressure conditions. Additionally, the gravitational force at the center of the Earth would be effectively zero, which is essential for the functioning of a simple pendulum.
What is the time period of simple pendulum at center of earth?
The time period of a simple pendulum at the center of the Earth would theoretically be zero because there is no gravitational force acting on it. A simple pendulum's period is determined by the acceleration due to gravity, which would be zero at the center of the Earth.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
How does altitude from the surface of earth affect the period of a simple pendulum?
The period of a simple pendulum is not affected by altitude from the surface of the Earth, as it is determined by the length of the pendulum and acceleration due to gravity, both of which are constant at different altitudes within reasonable ranges.
Why the motion of simple pendulum is slow at equator?
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
Can you conduct simple pendulum experiment at the centre of the earth?
It would not be possible to conduct a simple pendulum experiment at the center of the Earth due to extreme heat and pressure conditions. Additionally, the gravitational force at the center of the Earth would be effectively zero, which is essential for the functioning of a simple pendulum.
What is the time period of simple pendulum at center of earth?
The time period of a simple pendulum at the center of the Earth would theoretically be zero because there is no gravitational force acting on it. A simple pendulum's period is determined by the acceleration due to gravity, which would be zero at the center of the Earth.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
How the motion of simple pendulum is affected if it is placed at the center of earth?
If a simple pendulum is placed at the center of the Earth, it will experience zero net gravitational force because it is equidistant from all directions. As a result, the pendulum's motion would be unaffected and it would not swing back and forth due to the absence of a gravitational pull.
How does the Foucault pendulum work?
A Foucault pendulum demonstrates Earth's rotation by swinging in a consistent direction while the Earth rotates beneath it. The pendulum's swing appears to change due to the rotation of the Earth, creating a clockwise or counterclockwise motion depending on the hemisphere. This phenomenon reflects the inertia and conservation of angular momentum in the rotating reference frame of the pendulum.
What is the time period of simple pendulum at the center of the earth?
The time period of a simple pendulum at the center of the Earth would be almost zero. This is because there is no gravitational force acting at the center of the Earth due to a balanced pull in all directions. Thus, the pendulum would not experience any acceleration and would not oscillate.
What effect does the acceleration due to gravity on the moon have on a simple pendulum?
The lower acceleration due to gravity on the moon causes a simple pendulum to swing more slowly compared to Earth. The period of the pendulum is longer on the moon because gravity plays a role in determining the speed at which the pendulum swings back and forth.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
How earth's rotation affects a pendulum?
Earth's rotation affects a pendulum due to the Coriolis force, which causes the pendulum's plane of oscillation to rotate clockwise in the Northern Hemisphere and counterclockwise in the Southern Hemisphere. This rotation is a result of the pendulum's inertia attempting to maintain its orientation as Earth rotates underneath it. The Coriolis effect causes the apparent deflection of the pendulum's swing.
