A differentiator
As a sinusoidal signal is clipped the waveform approaches a square wave.
Triangular wave
This depends on the circuit in question. If the circuit only has resistors and maybe incandescent light bulbs, then with an equvalent RMS voltage of AC, to the previous DC, the circuit will behave almost the same. If the circuit has components such as capacitors and inductors, then the current will be shifted to flow at a waveform which no longer matches the voltage waveform. If you're talking about a circuit which was designed to run on a 12 volt battery, then you go and plug it into the wall, it will probably break, as the equivalent voltage causes a much higher current than these components were designed to handle.
You will need a regulator circuit that will change the shape of the pulse AND regulate the voltage to 5v.
The main advantage of using sinusoidal waveform is that any waveform can be represented using a sinusoidal wave (by applying Fourier series). Also, analysing a circuit (or any other system) becomes simpler and easier using sinusoidal signal as test signal.
it is DC powered, but can generate sawtooth or triangular wave AC if wired up properly. it cannot generate sine wave AC, although with an opamp wave shaping circuit the triangular AC waveform can be reshaped to a rough approximation of a sine wave.
As a sinusoidal signal is clipped the waveform approaches a square wave.
Triangular wave
It would be unity, or 1.0. Since the voltage in a DC circuit does not vary with time, there can be no phase displacement of the current waveform, and therefore the current could not lead or lag the voltage waveform.
It is an inverting comparator with a positive feedback, can convert an irregular shaped waveform to square waveform. it is also known as squaring circuit. sudhanshu kumar siliguri institute of tech. ece(2nd year)
If there are 58 defective circuit boards, two can be selected in 58*57/2 = 1653 ways.
If the circuit is square or rectangular then there will be four 90 degree elbows or bends required.
No , an AC waveform goes to 0 60 times a second ( if its a 60 hz wave form )
A COMPARATOR CIRCUIT WHICH CONVERTS ANY ARBITRARY SIGNAL(SLOPE!=1) TO SQUARE WAVEFORM IN SHORT A AMPLITUDE COMPARATOR
This depends on the circuit in question. If the circuit only has resistors and maybe incandescent light bulbs, then with an equvalent RMS voltage of AC, to the previous DC, the circuit will behave almost the same. If the circuit has components such as capacitors and inductors, then the current will be shifted to flow at a waveform which no longer matches the voltage waveform. If you're talking about a circuit which was designed to run on a 12 volt battery, then you go and plug it into the wall, it will probably break, as the equivalent voltage causes a much higher current than these components were designed to handle.
The frequency of the power waveform in a capacitive circuit, or for that matter, an inductive circuit, is the same as the input voltage or current. Its just that the current leads the voltage (capacitor) or lags the voltage (inductor) by a phase angle, the cosine of which is the power factor. It does not matter how many sine waves you have, or what their phase angle is; if they all have the same frequency, the resultant, by Fourier analysis, is still a sine wave of the same frequency.
Because power dissipated in rl circuit is given by p= 1/2(Li²)+ i²R which will give a curve and not a linear graph. Secondly the graph is a cosine curve ,with a phase difference between current and voltage. Hence the waveform is not symmetrical to x-axis .