The voltage of a circuit with a resistance of 250 ohms and a current of 0.95 amps is 237.5 volts. Ohms's law: Voltage = Current times Resistance
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Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
Ohm's Law: voltage is current times resistance, so 8 amps times 2 ohms is 16 volts.
Your current will be 30/R Amps. Where R is the resistance in Ohms.
Each resistor in a circuit performs a well defined function and its resistance is calculated by the circuit designer as the voltage across it divided by the current through it. Sometimes the value of resistance required is over 1,000,000 hms.
Current flowing through a device depends on resistance offered by that device.
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
16 volts
The resistance of a current is a measure of how difficult it is to push the electrons along.AnswerThere is no such thing as the 'resistance of a current'. Resistance is a characteristic of the material through which a current flows, not of the current itself.
yes
U = RxI so 11x20=220 volts
If resistance is high that time the current flow is low. Bcoz current always flow through the low resistance path.
resistance conductance or 1/resistance
Resistance
Resistance affects how much current can flow; a higher resistance means either less current, or more voltage required for the same current. They are related in formula by V = IR, i.e. the product of resistance and current is the voltage across that component. Knowing any two allows you to work out the third. ANSWER REMOVING IMPIRICAL MAGNETUDES IT IS SIMPLY A RATIO 1:1:1
A shunt resistance is a low resistance connected parallel to the galvanometer so that a large portion of current passes through the low resistance and a small fraction of current passes through the galvanometer this saves the galvanometer from damage
The formula you are looking for is V = IR where V = Voltage I = Current R = Resistance With some formula manipulation and numbers plugged in you get I = 120V / 9.6Ω I = 12.5A The kettle would have 12.5 volts of current running through it.
Resistance in the circuit makes it difficult for current to pass through.