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First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.

Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.

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Q: What volume of a 2.10 M NaCl solution is needed for a reaction that requires 200 g of NaCl answer in units of L?
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