answersLogoWhite

0


Best Answer

The temperature would be that of water's boilng point od 100 degrees

User Avatar

Wiki User

14y ago
This answer is:
User Avatar
More answers
User Avatar

AnswerBot

12h ago

The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Earth Science
Related questions

What is the total heat loss if you have 18 grams of aluminum and the temperature changes from 64 degrees Celsius to 48 degrees Celsius?

Approx 4974 Joules.


Is 50 grams 96 degrees Celsius 148 meters or 259 liters a measurement of volume?

50 grams and 96 degrees Celsius are not measurements of volume. The options provided are not related to volume either; 148 meters is a measurement of length and 259 liters is a measurement of volume.


If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?

105C


What is the density of warm water cold water and ice?

Density of ice at 0 degrees Celsius is 916.8 grams per cubic centimeter or milliliter. The density of fresh water is dependant on the temperature: At 3.98 degrees Celsius the density is 0.999975 grams per milliliter. At 100 degrees Celsius the density is 0.958.35 grams per milliliter.


What will the final temperature be if 688 calories of heat is released by 25 mL of water with an initial temperature of 80 degrees celsius?

Do some converting first. 688 calories (4.184 Joules/1 calorie) = 2878.592 Joules 25 ml of water = 25 grams q(Jolules) = mass * specific heat * (Temp. final - Temp. initial) 2878.592 Joules = 25 grams Water * 4.180 J/gC * (Temp Final - 80C ) 2878.592 Joiles = 104.5( Temp. Final) - 8360 11238.592 =104.5(Temp. Final) 107.55 Celsius Final Temperature ( call it 108 C )


What is the final equilibrium temperature when 15 grams of milk at 22 degrees Celsius is added to 185 grams of coffee at 86 degrees Celsius?

The final equilibrium temperature can be found using the principle of conservation of energy. The heat lost by the coffee as it cools down is equal to the heat gained by the milk as it warms up. Using the formula Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate the final temperature.


What is the final temperature of the mixture if 100gram of water at 70temperature is added to 200gram of cold water at 10temperature and well stirred?

The final temperature can be calculated using the principle of conservation of energy. The formula to use is: ( m_1c_1(T_f-T_1) = -m_2c_2(T_f-T_2) ), where (m_1c_1) is the mass and specific heat capacity of water at 70ºC, (T_f) is the final temperature, (m_2c_2) is the mass and specific heat capacity of water at 10ºC, and (T_1) and (T_2) are the initial temperatures. Substituting the values, we find the final temperature to be around 24ºC.


How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


Is gram used to measure the temperature in the metric system?

No, grams are unit of mass, not temperature. Temperature is measured in °C (degrees celsius) or for scientific work in 'K' K = °C + 273.15


How do you increase the the temperature of 500 grams of water from 20 degrees Celsius to 100 degrees Celsius?

To increase the temperature of 500 grams of water from 20°C to 100°C, you need to input energy in the form of heat. The amount of heat required can be calculated using the specific heat capacity of water (4.18 J/g°C) and the equation Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.


If 1200 calories of heat is added to 40 grams of water at 20 degree what will be the final temperature?

To find the final temperature, you can use the formula: heat gained = mass * specific heat capacity * temperature change. First, calculate the heat gained: 1200 calories = 40g * 1 cal/g°C * (final temperature - 20°C). Rearrange the formula to solve for the final temperature: final temperature = 1200 calories / (40g * 1 cal/g°C) + 20°C. Solving this gives the final temperature of 50°C.


The amount of dietary Calories in one hard-boiled egg could raise the temperature of?

1,000 grams of water by 75 degrees Celsius