The temperature would be that of water's boilng point od 100 degrees
The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.
To find the final temperature, you can use the formula: heat gained = mass * specific heat capacity * temperature change. First, calculate the heat gained: 1200 calories = 40g * 1 cal/g°C * (final temperature - 20°C). Rearrange the formula to solve for the final temperature: final temperature = 1200 calories / (40g * 1 cal/g°C) + 20°C. Solving this gives the final temperature of 50°C.
The density of sulfur at 25 degrees Celsius is approximately 2 grams per cubic centimeter.
The density of water at 37 degrees Celsius is around 0.988 grams per cubic centimeter. At this temperature, water is slightly less dense compared to when it is at 4 degrees Celsius, where it has a density of 1.000 grams per cubic centimeter.
The density of water at 100 degrees Celsius is about 0.9584 grams per cubic centimeter. At this temperature, water is in its liquid state and expands slightly compared to when it is at its maximum density at 4 degrees Celsius.
It takes more heat to melt 12 grams of mercury (Hg) as it has a higher melting point compared to methane (CH4). Mercury has a melting point of -38.83 degrees Celsius, while methane melts at -182.5 degrees Celsius.
Approx 4974 Joules.
50 grams and 96 degrees Celsius are not measurements of volume. The options provided are not related to volume either; 148 meters is a measurement of length and 259 liters is a measurement of volume.
105C
Density of ice at 0 degrees Celsius is 916.8 grams per cubic centimeter or milliliter. The density of fresh water is dependant on the temperature: At 3.98 degrees Celsius the density is 0.999975 grams per milliliter. At 100 degrees Celsius the density is 0.958.35 grams per milliliter.
Do some converting first. 688 calories (4.184 Joules/1 calorie) = 2878.592 Joules 25 ml of water = 25 grams q(Jolules) = mass * specific heat * (Temp. final - Temp. initial) 2878.592 Joules = 25 grams Water * 4.180 J/gC * (Temp Final - 80C ) 2878.592 Joiles = 104.5( Temp. Final) - 8360 11238.592 =104.5(Temp. Final) 107.55 Celsius Final Temperature ( call it 108 C )
The final equilibrium temperature can be found using the principle of conservation of energy. The heat lost by the coffee as it cools down is equal to the heat gained by the milk as it warms up. Using the formula Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate the final temperature.
The final temperature can be calculated using the principle of conservation of energy. The formula to use is: ( m_1c_1(T_f-T_1) = -m_2c_2(T_f-T_2) ), where (m_1c_1) is the mass and specific heat capacity of water at 70ºC, (T_f) is the final temperature, (m_2c_2) is the mass and specific heat capacity of water at 10ºC, and (T_1) and (T_2) are the initial temperatures. Substituting the values, we find the final temperature to be around 24ºC.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
No, grams are unit of mass, not temperature. Temperature is measured in °C (degrees celsius) or for scientific work in 'K' K = °C + 273.15
To increase the temperature of 500 grams of water from 20°C to 100°C, you need to input energy in the form of heat. The amount of heat required can be calculated using the specific heat capacity of water (4.18 J/g°C) and the equation Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.
To find the final temperature, you can use the formula: heat gained = mass * specific heat capacity * temperature change. First, calculate the heat gained: 1200 calories = 40g * 1 cal/g°C * (final temperature - 20°C). Rearrange the formula to solve for the final temperature: final temperature = 1200 calories / (40g * 1 cal/g°C) + 20°C. Solving this gives the final temperature of 50°C.
1,000 grams of water by 75 degrees Celsius