What would happen to the rate of a reaction with rate law rate k NO2H2 if the concentration of NO were halved?
the rate would be one fourth
What would happen to the rate of a reaction with rate law rate k no 2 h2 if the concentration of h2 were halved-?
What is the order of reaction if the half life of a reaction is halved as the initial concentration of the reactant is doubled.?
Second order. If the half life of a reaction is halved as the initial concentration of the reactant is doubled, it means that half life is inversely proportional to initial concentration for this reaction. The only half life equation that fits this is the one for a second-order reaction. t(1/2) = 1/[Ao]k As you can see since k remains constant, if you double [Ao], you will cause t(1/2) to be halved.
What would happen to the rate of a reaction with rate law ratekNO2H2 if the concentratin of H2 were halved?
Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
The effect of concentration of reactants on rate of reaction depends on the ORDER of the reaction. For many reactions, as the concentration of reactants increases, the rate of reaction increases. There are exceptions however, for example a zero order reaction where the rate of reaction does not change with a change in the concentration of a reactant.
What would happen to the rate of a reaction with rate law rate kNO2H2 if the concentration of NO were double?
What is the relation between an concentration of an reactants and the products which it is in an state of equilibrium?
The rate(speed) of a reaction is directly related to the concentration of the enzyme. As the concentration of the enzyme increases, the speed of a reaction will increase. This is because the more concentrated the enzyme concentration, the more particles there are to collide and react. There will be a stronger concentration of enzyme to react with the substrate.