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58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
2.79
When NaCl is added to water, you would observe that it dissolves quite readily.
To prepare a 0.9% solution take 0.9grams NaCl and dilute with 100mls of water.
10 g of NaCl in 2 kg of water is 5 g of NaCl in 1 kg of water.The molar mass of NaCl is 39,666 g.5 g is equal to 0,318 molal.
Convert the 200 mol of water to kilograms of water.
Convert the 200 mol of water to kilograms of water.
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
Convert the 200 mol of water to kilograms of water.
The concentration of NaCl is 263 g/L
convert the .2 kg of NaCl to moles of NaCl.
Molality(m)= moles of solute divided by kilograms(kg) of solvent you need to find the moles of NaCl by using a conversion factor 70g NaCl = 1mol divided by 58.44g NaCl =1.20mol then you need to convert 300g of water which is the solvent to kilograms by moving the decimal over 3 units to the left which makes .300 kg of solvent Molality= 1.20mol divided by .300kg Molality=4.00
2.79
0.630 g NaCl x (1 mol NaCl/58.44 g NaCl) = 0.0108 mol NaCl525 g H2O x (1 kg/1000g) = 0.525 kg H2O0.0108 mol NaCl/0.525 kg H2O = 0.0206 molality
2mol/kg
The answer is 0,505.