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What would you needto do to calculate the molality to 10 molecules of NaCl in 200 molecules of water?
Wiki User
∙ 11y ago
Molality of a solution is defined as the number of gram moles, for molecular compounds, or gram formula unit masses, for ionic compounds, mixed with each kilogram of solvent. Sodium chloride is the solute in the question, and water is the solvent.
Avogadro's Number is defined as the number of formula units required to constitute one gram formula unit and has the value of about 6.022 X 1023. Therefore, 10 formula units of NaCl constitutes 10/(6.022 X 1023) or about 1.6606 X 10-23 gram formula unit.
The gram molecular mass of water is 18.0518. Therefore, 200 molecules of water contains (200)(18.0518)/(6.022 X 1023) or about 599.5 X 10-23 grams or 0.5995 X 10-23) kilograms.
Therefore, the molality of the given mixture is 1.6606/0.59995* or about 2.768.
________
*The number 10-23 appears in both numerator and denominator, and therefore need not be included in this fraction.
Wiki User
∙ 11y ago
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When a certain amount of calcium chloride (CaCl2) was dissolved 100.g of water the boiling point rose from 100.0C to 104.4C calculate the molality of this solution.?
Delta T = imKI = van't Hoff factor = 3 for CaCl2 m = molality = moles solute/kg solvent = ? K = boiling point constant for water = 0.512 Delta T = change in temperature = 4.4 deg C Plug in the values and solve for m
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
How do you calculate the total number of atoms found in seven molecules of water?
One water molecule of water has three atoms (2H + 1O = H2O). Seven molecules of water has 21 total atoms ( 3 x 7 = 21).
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution composed of 20.2 g NaCl dissolved in 685 g of water?
The answer is 0,505.
What would you need to do to calculate the molality of 10 mol of NaCl in 200 mols of water?
Convert the 200 mol of water to kilograms of water.
What would you need to do to calculate the molality of 10 mol NaCl in 200 mol of water?
Convert the 200 mol of water to kilograms of water.
What would you need to do to calculate the molality of 10 mol of NaCl in 200 mol of water?
Convert the 200 mol of water to kilograms of water.
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The molality is 0,07.
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This molality is 90,08 g/kg.
What would you need to do to calculate the molality of 10 g of NaCl in 2kg of water?
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
What would you need to do to calculate the molality of 10 g of NaCl in 2kg water?
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of ethanol will be 5,91.
What is the molality of 14.3g of sucrose in 676g of water?
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When does molarity and molality become equal?
In dilute solutions... ie closer a solution is to pure water the closer molality and molarity come to equalling each other. This is because the molality uses mass and molarity uses volume, the ratio of these two (mass and volume) is density, and water has the density of 1 therefore the mass and volume are equal to each other. THEREFORE calculating the molarity of water is the same as calculating the molality of water.
When a certain amount of calcium chloride (CaCl2) was dissolved 100.g of water the boiling point rose from 100.0C to 104.4C calculate the molality of this solution.?
Delta T = imKI = van't Hoff factor = 3 for CaCl2 m = molality = moles solute/kg solvent = ? K = boiling point constant for water = 0.512 Delta T = change in temperature = 4.4 deg C Plug in the values and solve for m
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
