200 calories, or approx. 47.84 joules
J/g x C is the equation for heat capacity.
Energy is actually given off in the lowering of temperature. Use the equation Q = mc(change in T). In this case, m = 2.9, c = 4.179 J, and change in T = -12.1 degree C. Now solve for Q, the heat energy. This exothermic process gives off approximately 146.6 J of heat.
I must assume that the ice block is at an initial temperature of 0o C. I also need to work in joules,. so I will convert the calories to joules. 1600 cal. (4.184 joule/1 cal.) = 6694.4 joules -------------------- 6694.4 J = (20 grams H2O)(4.180 J/gC)(Tf - 0o C) 6694.4/83.6 = Tf = 80o Celsius ==========
The specific latent heat/ latent heat of fusion of ice is 333.55 J/gtherefore by using the equation E=mLE = 54 * 333.55= 18011.7 JTherefore the energy needed to melt 54 grams of ice at its melting point which is keeping it at 0 degrees Celsius is 18011.7 Joules.
The specific heat of iron is either 0.46 or 0.45 Jolules/grams*Celsius, so......... q(in Joules) = mass * specific heat * Temp final - Temp. initial q = (65 grams Fe)(0.46 J/gC)(95 C - 25 C) = 2093 joules of energy
0000000000000000.11 joules
Voltage is electrical pressure and Joules is a power rating so other info is needed
40.79 H2O kj/moles x 1 moles/18 grams= 2.266/1000=0.002266 joules/grams
If fifty grams of water cooled from 50 degrees to 10 degrees, and the specific heat of water is 4.2, 135 kJ of heat was released.
In principle, those two things measure different things (mass, and energy). To get the mass associated with a certain amount of energy, divide the number of joules (1 kJ = 1000 joules) by the square of the speed of light, i.e., divide by 9 x 1016 (m2/sec2). The answer is in kilograms; you an multiply this answer by 1000 to convert into grams.
The unit for specific heat is Joules/g-Kelvin or it can be Joules/g-Celsius J= Joules g= Grams C= Celsius
226,ooo j
2520 Joules = (X)(4.180J/gC)(30C-10C) 2520J = 83.6X 30.14 grams of water.
2,26 Kj are necessary
Lets say, for example the enthalpy is equal to 1200 joules/gram. You take 1200 joules/gram * (# of grams)/one mole [now you can cancel grams and it is now joules/mole.] Then convert the answer to kilojoules by dividing by 1000.
What is the total number of Joules of heat absorbed by 65.00 grams of water when the temperature of th water is raised from 25.00 C to 40.00 C
226,ooo j