To calculate the heat released when cooling water, you can use the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the substance (20g in this case), c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (10°C in this case). Plugging in the values, we get Q = 20g x 4.18 J/g°C x 10°C = 836 J. Therefore, 836 joules of heat are released when 20 grams of water is cooled from 20°C to 10°C.
Energy is actually given off in the lowering of temperature. Use the equation Q = mc(change in T). In this case, m = 2.9, c = 4.179 J, and change in T = -12.1 degree C. Now solve for Q, the heat energy. This exothermic process gives off approximately 146.6 J of heat.
This calculation is used to find the specific heat capacity of a substance. The specific heat capacity is a measure of how much energy is needed to raise the temperature of a given amount of a substance by 1 degree Celsius. The formula used is: specific heat capacity = energy (in Joules) / (mass (in grams) * change in temperature (in Celsius)).
The specific heat of iron is either 0.46 or 0.45 Jolules/grams*Celsius, so......... q(in Joules) = mass * specific heat * Temp final - Temp. initial q = (65 grams Fe)(0.46 J/gC)(95 C - 25 C) = 2093 joules of energy
The molar mass of sulfur is 32.06 g/mol. To find the mass of 6.02 x 10^23 atoms of sulfur, first calculate the number of moles by dividing the number of atoms by Avogadro's number (6.02 x 10^23 atoms/mol). Then, multiply the number of moles by the molar mass of sulfur to get the mass in grams.
To find the number of moles of Na in 42 grams, we can use the molar mass of Na, which is approximately 23 grams/mol. First, calculate the number of moles by dividing the given mass by the molar mass: 42 grams / 23 grams/mol = 1.83 moles of Na.
The energy released when 6 grams of water is condensed from water vapor is equal to the heat of vaporization of water. This is approximately 2260 joules per gram. So, for 6 grams of water, the total energy released would be around 13,560 joules.
The energy released when condensing water vapor is known as the heat of condensation. It takes 2260 Joules of energy to condense 1 gram of water vapor. So, for 6.0 grams of water vapor, the energy released would be 6.0 grams * 2260 Joules/gram = 13,560 Joules.
0000000000000000.11 joules
When 2 grams of water is converted from liquid to gas at its boiling point, it requires an input of approximately 2260 joules of energy. Conversely, when 2 grams of steam condenses into liquid water, it releases around 2260 joules of energy.
Voltage is electrical pressure and Joules is a power rating so other info is needed
In principle, those two things measure different things (mass, and energy). To get the mass associated with a certain amount of energy, divide the number of joules (1 kJ = 1000 joules) by the square of the speed of light, i.e., divide by 9 x 1016 (m2/sec2). The answer is in kilograms; you an multiply this answer by 1000 to convert into grams.
The unit for specific heat is Joules/g-Kelvin or it can be Joules/g-Celsius J= Joules g= Grams C= Celsius
226,ooo j
2,26 Kj are necessary
The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.
96.3 Joules
Grams Liquid x mol/g x Hfusion