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Its Lattice energy is greater than the solvation energy of water.
yes
because it lower than Ba as you go down ionization energy increases
Thebond energy in an atomic nucleus are greater than the energy of chemical bonds.The binding enegy of a nucleon is 7,6 MeV.
Hydration Energy is involved in the solution process. The solution process involves three steps all including a change in enthalpy. The first delta H (change in enthalpy) is the process by which water molecules overcome attractive forces in the solute particles to break chemical bonds. This process is endothermic. The second step delta H 2 is the separation of solvent molecules to accommodate the solute. This step also requires energy and is endothermic (delta H is greater than 0) The final step is the formation of new attractive interactions between solute and solvent particles and is exothermic (delta H is less than 0). The sum of delta H 1, 2, and 3 is the overall enthalpy of the solution process and this sum is known as the hydration energy. If the sum of delta H 1 and 2 is greater in magnitude than the delta H 3 (which is a negative number) the overall process will be endothermic. If the sum of delta H 1 and 2 is lesser in magnitude than delta H 3 the overall process will be exothermic.
Yes. Because hydration energy of Na+ is greater than K+. More the hydration energy greater is solubility. A compound is soluble if hydration energy is greater than lattice energy.
Its Lattice energy is greater than the solvation energy of water.
Group Two elements form oxide consisting of ionic bonds. With that in mind, as you go down group two, the ionic radius increases due to an addtion of a electron shell, so therefore, melting point of group2 oxide decreases down group because the distance between the O2- and Group two ion are further apart. The increase of bond length results in less energy needed to break the ionic bonds, resulting in decrease of energy.
The lattice energy of potassium bromide is more exothermic than the lattice energy of rubidium iodide because lattice energy is inversely proportional to atomic radius.
Ionic compounds can only be dissolved in water if the energy of hydration is greater than latice energy of that compound
The bonds in compound A are stronger than the bonds in compound B.
Lattice energy increases with greater charge and smaller size. Since the charges are the same for both compounds, you have to look at the sizes of the atoms, K and Na, and since both have Cl, you don't have to compare that with anything. K is larger than Na, so since NaCl has a smaller size and the same charge, it has higher lattice energy.
because Mg and O have more electropositivity and electronegativity rspt. than Na and Cl atoms.
Cao or CaS have a higher lattice energy
since ca2+ has a larger atomic radii compared to Mg2+ (and the same for F and CL2), the electrons are dispersed over a wider surface area and so have a lesser strength than that of magnesium. Hence, with a smaller atomic radii, Magnesium has stronger attractive forces with require more energy to be broken and therefore making it more exothermic than calcium.
It is a matter of lattice energy vs. heat of solution. The lattice energy is the energy change associated with the ions in the gas phase forming a solid (crystalline) lattice. It is typically an exothermic process, liberating energy. The heat of solution is the energy change associated with the ions being dissolved by solvent, and can be exothermic or endothermic. If the heat of solution is more exothermic than the lattice energy, than it is energetically favorable for the ionic compound to be solvated. If the lattice energy is more exothermic, than solvation will not occur.
Okay to be honest, I'm not entirely sure, but I think its false because the larger the positive or negative charge of the ion, the greater lattice energy it has.According to the answers of similar questions, I think it's true.